Question

(Python)

######new part: append method
######we have a list
##lis = [1,'a',8, 0]
##print(lis)
########to append "yes" to the list:
##lis.append('yes')
##print(lis)
########index method: let us find the index of 'yes':
##index_yes = lis.index('yes')
##print(index_yes) ## here you cam see that it is 4, as it must be
########insert method: we want to put 'o, no!' in the list at the first place:
##lis.insert(0, 'o,no!')
##print(lis)
########### sort method: we wnat to sort out list; for our regrets sorting is
###########possible only for same kind of data: list must be all numeric of
##########string.
##########We split our list for string part (lis_str) and numeric part (lis_num):
##########here is our list now: lis = ['o,no!', 1, 'a', 8, 0, 'yes']
######### numeric items have indeces 1,3,4, string items: 0,2,5.
##num = [1,3,4]
##stri = [0,2,5]
#########let us use the trick:
##lis_num = [lis[i] for i in num]
##lis_stri = [lis[i] for i in stri]
#########checking:
##print(lis_num)
##print(lis_stri)
#########let us sort them:
##lis_num.sort()
##lis_stri.sort()
#########cheking:
##print(lis_num)
##print(lis_stri)
######################TASK 2. For the list liss do the following:
##liss = ['o,no!', -1, 'why?', 8, 0, 'yes', 'not, really']
#####append "hi" to the end
#####find the index of "yes" in the new liss list
#####insert 'what?' to the third place
#####extract string part of the liss and sort it
####$$$$$$$$ If your code works - it is acceptable, if it does not - it is not acceptable.

#########remove and del
######## let us get the list
##li = [1, 2, 6, 'yes']
##########we want to remove the item 2:
##li.remove(2)
##print(li)
###########we want to delete the element with index 2 from the new list li:
##del li[2]
##print(li)

Answer 1

If you have any doubts, please give me comment...

####new part: append method

####we have a list

lis = [1,'a',8, 0]

print(lis)

######to append "yes" to the list:

lis.append('yes')

print(lis)

######index method: let us find the index of 'yes':

index_yes = lis.index('yes')

print(index_yes) ## here you cam see that it is 4, as it must be

######insert method: we want to put 'o, no!' in the list at the first place:

lis.insert(0, 'o,no!')

print(lis)

######### sort method: we wnat to sort out list; for our regrets sorting is

#########possible only for same kind of data: list must be all numeric of

########string.

########We split our list for string part (lis_str) and numeric part (lis_num):

########here is our list now: lis = ['o,no!', 1, 'a', 8, 0, 'yes']

####### numeric items have indeces 1,3,4, string items: 0,2,5.

num = [1,3,4]

stri = [0,2,5]

#######let us use the trick:

lis_num = [lis[i] for i in num]

lis_stri = [lis[i] for i in stri]

#######checking:

print(lis_num)

print(lis_stri)

#######let us sort them:

lis_num.sort()

lis_stri.sort()

#######cheking:

print(lis_num)

print(lis_stri)

####################TASK 2. For the list liss do the following:

liss = ['o,no!', -1, 'why?', 8, 0, 'yes', 'not, really']

###append "hi" to the end

liss.append("hi")

print(liss)

###find the index of "yes" in the new liss list

index_hi = liss.index("yes")

print(index_hi)

###insert 'what?' to the third place

liss.insert(2, 'what?')

print(liss)

###extract string part of the liss and sort it

liss_str = [el for el in liss if type(el) is str]

liss_str.sort()

print(liss_str)

##$$$$$$$$ If your code works - it is acceptable, if it does not - it is not acceptable.

#######remove and del

###### let us get the list

li = [1, 2, 6, 'yes']

########we want to remove the item 2:

li.remove(2)

print(li)

#########we want to delete the element with index 2 from the new list li:

del li[2]

print(li)