Private nonprofit four-year colleges charge, on average, $26,582
per year in tuition and fees. The standard deviation is $6,549.
Assume the distribution is normal. Let X be the cost for a randomly
selected college. Round all answers to 4 decimal places where
possible.
a. What is the distribution of X? X ~ N(Correct,Correct)
b. Find the probability that a randomly selected Private nonprofit
four-year college will cost less than 27,140 per year.
Incorrect
c. Find the 66th percentile for this distribution. $ (Round to the
nearest dollar.)
Given that, mean (μ) = $26582 and
standard deviation = $6549
a) X ~ N(26582, 6549)
b) We want to find, P(X < 27140)
Therefore, required probability is 0.5359
b) We want to find, the value of x such that, P(X < x) = 0.66
Therefore, the 66th percentile for this distribution is $29267
Note : if we used z-score = 0.41246 instead of 0.41 then we will get, 66th percentile is $29283
Using Excel we get, z-score is,
Excel Command : NORMSINV (0.66) = 0.41246
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