Question

- A random sample of 82 college students shows only 32 are
registered to vote. What is the 99% confidence interval for the
percentage of college students who are registered to vote?
- (0.2847, 0.4958)
- (0.3902, 0.6748)
- (0.2515, 0.5290)
- (0.3127, 0.4678)

Answer #1

In a random sample of 400 registered voters, 144 indicated they
plan to vote for Candidate A.
Determine a 95% confidence interval for the proportion of all
the registered voters who will vote for Candidate A.
Value from the appropriate table=
Margin of error=
Lower limit of C.I.=
Upper limit of C.I.=

A statistics professor asked her students whether or not they
were registered to vote. In a sample of 52 of her students
(randomly sampled from 700 students), 34 said they were registered
to vote.
1. Find a 95% confidence interval for the true proportion of the
professor's students who were registered to vote. (Make sure to
check any necessary conditions and to state a conclusion in the
context of the problem.)
2. A reader of the results concludes that "I...

Suppose only 45% of the American people who registered to vote
actually intended to vote in the 2016 presidential election.
You take a random sample of 2 Americans who are registered to
vote. Using the appropriate method, find the chance that at most 1
of them actually intends to vote in the 2016 presidential election.
Identify the method used.
You take a random sample of 20 Americans who are registered to
vote. Using the appropriate method, find the chance that...

A random sample of 337 college students was asked whether or not
they were registered to vote. We wonder if there is an association
between a student’s sex and whether the student is registered to
vote. The data are provided in the tables below (expected counts
are in parentheses). (All the conditions are satisfied - don’t
worry about checking them.)
The calculated statistic is χ 2 = 0.249 , and the
P-value = 0.618.
State your complete conclusion in...

3. A random sample of 78 students was interviewed, and 59
students said that they would vote for Jennifer McNamara as student
body president.
a.Let p represent the proportion of all students at this
college who will vote for Jennifer. Find a point estimate for p.
Round your answer to the nearest hundredth.
b.Find a 90% confidence interval for p. Round your answer to
the nearest hundredth and THEN change them to a percentage.
c.Interpret the meaning of the confidence...

A random sample of registered voters were asked about an issue
on the ballot of an upcoming election. The proportion of those
surveyed who plan to vote "Yes" on the issue is 0.54 , with a
margin of error of 0.06 . Construct a confidence interval for the
proportion of registered voters that plan to vote "Yes" on the
issue.

Based on a simple random sample of 1440 college students, a 97%
confidence interval for the percentage of students who receive
financial aid is reported as 82.99% ±± 2.5%. Which of the following
is/are correct interpretation(s) of this confidence interval?There
may be more than one correct answer; you must check all correct
answers in order to get credit for this problem.
A. If we select an individual from the population,
there is a 97% probability that this individual is one...

The student council at a nearby university reports that only 35%
of the student body is registered to vote.
A statistics professor asked her students whether or not they
were registered to vote. In a sample of 63 of her students
(randomly sampled from her 700 students), 29 said they were
registered to vote.
What is the sample proportion? Round to 4 decimal
places.
Describe the sampling distribution of the proportion of
students who are registered to vote. Include a...

Ages of students: A simple random sample of 100
U.S. college students had a mean age of 22.68 years. Assume the
population standard deviation is σ = 4.74 years. Construct
a 99% confidence interval for the mean age of U.S. college
students.
The answer I posted my instructor says it is wrong. I came up
with 21.45 to 23.91 a 99% confidence interval for the mean of the
U.S college students
She said the z procedures are needed.
Thanks.

A random sample of ?=1000 registered voters and found that 520
would vote for the Republican candidate in a state senate race. Let
? represent the proportion of registered voters who would vote for
the Republican candidate.
Consider testing
?0:?=.50
??:?>.50
(a) The test statistic is ?z =
(b) Regardless of what you acutally computed, suppose your
answer to part (a) was z = 1.28. Using this z, p-value =

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