Question

Based on a simple random sample of 1440 college students, a 97% confidence interval for the...

Based on a simple random sample of 1440 college students, a 97% confidence interval for the percentage of students who receive financial aid is reported as 82.99% ±± 2.5%. Which of the following is/are correct interpretation(s) of this confidence interval?There may be more than one correct answer; you must check all correct answers in order to get credit for this problem.

A. If we select an individual from the population, there is a 97% probability that this individual is one of the of students who receive financial aid.
B. In any simple random sample of 1440 college students from the population, there is a 97% probability that the percentage of students who receive financial aid in the sample is within 2.5% of the percentage of students who receive financial aid in the entire population.
C. There is a 97% probability that the true percentage of students who receive financial aid is between 80.49% and 85.49%.
D. There is a 97% probability that the true percentage of students who receive financial aid is within 2.5% of 82.99%.
E. The percentage of college students in the population of students who receive financial aid is between 80.49% and 85.49%.
F. In 97% of all samples of size 1440 from this population, the percentage of students who receive financial aid is between 80.49% and 85.49%.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Based on a simple random sample of size 90, an 84% confidence interval for the unknown...
Based on a simple random sample of size 90, an 84% confidence interval for the unknown mean SAT MATH score, μμ, in some large population is 517<μ<525517<μ<525. Which of the following is/are correct interpretation(s) of this confidence interval?There may be more than one correct answer; you must check all correct answers in order to get credit for this problem. A. 84% of individuals in this sample have a mean SAT MATH score between 517 and 525. B. 84% of individuals...
A student was asked to find a 98% confidence interval for the population proportion of students...
A student was asked to find a 98% confidence interval for the population proportion of students who take notes using data from a random sample of size n = 84. Which of the following is a correct interpretation of the interval 0.1 < p < 0.33? Check all that are correct. ____With 98% confidence, the proportion of all students who take notes is between 0.1 and 0.33. ____The proprtion of all students who take notes is between 0.1 and 0.33,...
A student was asked to find a 90% confidence interval for the proportion of students who...
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 88. Which of the following is a correct interpretation of the interval 0.1 < p < 0.3? Check all that are correct. The proprtion of all students who take notes is between 0.1 and 0.3, 90% of the time. There is a 90% chance that the proportion of notetakers in a sample...
A student was asked to find a 90% confidence interval for the proportion of students who...
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 84. Which of the following is a correct interpretation of the interval 0.1 < p < 0.31? Check all that are correct. With 90% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.1 and 0.31. There is a 90% chance that the proportion of...
A student was asked to find a 90% confidence interval for the proportion of students who...
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 78. Which of the following is a correct interpretation of the interval 0.13 < p < 0.27? Check all that are correct. 0 There is a 90% chance that the proportion of the population is between 0.13 and 0.27. 0 The proprtion of all students who take notes is between 0.13 and...
Ages of students: A simple random sample of 100 U.S. college students had a mean age...
Ages of students: A simple random sample of 100 U.S. college students had a mean age of 22.68 years. Assume the population standard deviation is σ = 4.74 years. Construct a 99% confidence interval for the mean age of U.S. college students. The answer I posted my instructor says it is wrong. I came up with 21.45 to 23.91 a 99% confidence interval for the mean of the U.S college students She said the z procedures are needed. Thanks.
In an simple random sample of 200 college students, 114 said that they usually speed on...
In an simple random sample of 200 college students, 114 said that they usually speed on interstate highways by 10 mph or more. Give a 95% confidence interval for the corresponding proportion for all college students. a: (0.5014,0.6455) b: (0.5431,0.6386) c: (0.3567,0.4533) d: (0.5014,0.6386)
20% of all college students volunteer their time. Is the percentage of college students who are...
20% of all college students volunteer their time. Is the percentage of college students who are volunteers different for students receiving financial aid? Of the 363 randomly selected students who receive financial aid, 58 of them volunteered their time. What can be concluded at the α = 0.10 level of significance? For this study, we should use The null and alternative hypotheses would be: H 0 : (please enter a decimal) H 1 : (Please enter a decimal) The test...
15% of all college students volunteer their time. Is the percentage of college students who are...
15% of all college students volunteer their time. Is the percentage of college students who are volunteers larger for students receiving financial aid? Of the 332 randomly selected students who receive financial aid, 53 of them volunteered their time. What can be concluded at the α= 0.05 level of significance? The test statistic is ? The p-value = (Please show your answer to 4 decimal places.)
Use the given degree of confidence and sample data to construct a confidence interval for the...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal places. When 267267 college students are randomly selected and​ surveyed, it is found that 101101 own a car. Find a​ 99% confidence interval for the true proportion of all college students who own a car.