Question

A piece of ice at 0 0C is put in 2.00 Kg of water at 20...

A piece of ice at 0 0C is put in 2.00 Kg of water at 20 0C. The equilibrium temperature of the system becomes 5 0C. (Lf=333 kJ/Kg, cw=4186 J/Kg, TK=TC+273.15)

a) Find the mass of ice?
Kg

b) Find the entropy change of ice?
J/K

c) Find the entropy change of water?
J/K

d) Find the total entropy change of sysem?
J/K

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
P-7: A piece of ice at 0 0C is put in 2.00 Kg of water at...
P-7: A piece of ice at 0 0C is put in 2.00 Kg of water at 20 0C. The equilibrium temperature of the system becomes 5 0C. (Lf=333 kJ/Kg, cw=4186 J/Kg, TK=TC+273.15) a) Find the mass of ice? Kg b) Find the entropy change of ice? J/K c) Find the entropy change of water? J/K d) Find the total entropy change of sysem? J/K
1.2 kg piece of ice at 0 oC is thrown into a very large lake at...
1.2 kg piece of ice at 0 oC is thrown into a very large lake at 12 oC. Water: Lf = 334 kJ/kg c = 4.19 kJ/(kg Co) A) What is the entropy change of the ice? deltaS = ???J/K B) What is the total entropy change of the ice and lake system? deltaS = ???J/K I NEED NUMBERS PLEASE
An insulated Thermos contains 115 g of water at 78.7 ˚C. You put in a 10.0...
An insulated Thermos contains 115 g of water at 78.7 ˚C. You put in a 10.0 g ice cube at 0.00 ˚C to form a system of ice + original water. The specific heat of liquid water is 4190 J/kg•K; and the heat of fusion of water is 333 kJ/kg. What is the net entropy change of the system from then until the system reaches the final (equilibrium) temperature?
An insulated Thermos contains 113 g of water at 77.3 ˚C. You put in a 10.3...
An insulated Thermos contains 113 g of water at 77.3 ˚C. You put in a 10.3 g ice cube at 0.00 ˚C to form a system of ice + original water. The specific heat of liquid water is 4190 J/kg•K; and the heat of fusion of water is 333 kJ/kg. What is the net entropy change of the system from then until the system reaches the final (equilibrium) temperature?
An insulated Thermos contains 119 g of water at 75.1 ˚C. You put in a 9.16...
An insulated Thermos contains 119 g of water at 75.1 ˚C. You put in a 9.16 g ice cube at 0.00 ˚C to form a system of ice + original water. The specific heat of liquid water is 4190 J/kg•K; and the heat of fusion of water is 333 kJ/kg. What is the net entropy change of the system from then until the system reaches the final (equilibrium) temperature?
How much heat is required to change m=1kg of ice at -6°C into water at 60°C?...
How much heat is required to change m=1kg of ice at -6°C into water at 60°C? cw= 4190 J/kg*K (specific heat of water), Lf= 333 kJ/kg (latent heat of fusion of ice), cice= 2100 J/kg*K
A small piece of ice (mass = 0.10 kg) at an initial temperature of 0oC is...
A small piece of ice (mass = 0.10 kg) at an initial temperature of 0oC is placed within glass of water, where the water's mass is 0.40 kg and it is at an initial temperature of 30oC.   (a) What is the final temperature of the system when thermal equilibrium is achieved assuming no heat leaks? (b) What is the entropy change of just the ice only while it melts? The latent heat of fusion and specific heats of ice and...
An 11 g ice cube at -12˚C is put into a Thermos flask containing 145 cm3...
An 11 g ice cube at -12˚C is put into a Thermos flask containing 145 cm3 of water at 24˚C. By how much has the entropy of the cube-water system changed when a final equilibrium state is reached? The specific heat of ice is 2200 J/kg K and that of liquid water is 4187 J/kg K. The heat of fusion of water is 333 × 103 J/kg. and A 6.0 g ice cube at -21˚C is put into a Thermos...
An insulated container has 2.00kg of water at 25◦C to which an unknown amount of ice...
An insulated container has 2.00kg of water at 25◦C to which an unknown amount of ice at 0◦C is added. The system comes to an equilibrium temperature of 20◦C. The heat capacity for water is 4190 J and the heat of fusion for ice is kg·K kJ LF =334kg. (a) Determine the amount of ice that was added to the water. (b) What is the change in the entropy associated with the ice melting? (c) What is the change in...
17. How much heat is required to change the temperature of 50 g of ice cube...
17. How much heat is required to change the temperature of 50 g of ice cube initially at - 30 0C to steam at 160 0C? (Express your answer in J){ specific heat of ice is 2090 J/kg 0C, that of water is 4186 J/kg 0C, that of steam is 2010 J/kg 0C; Lf = 3.33 X 10 J/kg, Lv = 2.26 X 10 J/kg.}
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT