The electric potential at a position located a distance of 22.8 mm from a positive point charge of 7.10×10-9C and 13.6 mm from a second point charge is 1.10 kV. Calculate the value of the second charge.
The answer is NOT -2.56x10^-3C/
Please provide answer in proper units.
soe =) charge (9.1) - 7,10x109 3) polachiall) = 1.10X103 u =) »,- 22.8 x16?m; 31:13.6X163 m che love; =) pollutial (1) = Litva 5) poftufial() = *(7 + 232 5) 0./aaxbo6= 0.3113106+ 3.6X163 =) Chorge (92) = (3,6x103)(0.122x10 6.0.311x107 51 Cloge (W) = 3.6x203(-0.189x106) => clonge (92) = -0.68x10^9 )
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