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A rod of length l=2.2m and mass M= 9.7kg joins two particles with masses m1 =12.9kg...

A rod of length l=2.2m and mass M= 9.7kg joins two particles with masses m1 =12.9kg and m2 = 5.0kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod with the linear speed of the masses of v= 12.9 m/s. (Moment of inertia of a uniform rod rotating about its center of mass

I=

1
12

M l2

)

a) Calculate the total moment of inertia of the system
I = kg m 2
b) What is the magnitude of the angular momentum about the origin?

L= kg m2 /s
c)If the length of the rod reduces to l=1.1m. What will be the final angular speed ωf?

ωf = rad/s

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