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A rod of length l=1.1m and mass M= 5.5kg joins two particles with masses m1 =4.8kg...

A rod of length l=1.1m and mass M= 5.5kg joins two particles with masses m1 =4.8kg and m2 = 2.8kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod with the linear speed of the masses of v= 3.5 m/s. (Moment of inertia of a uniform rod rotating about its center of mass I= 1 12 M l2 ) angularmomentum a) Calculate the total moment of inertia of the system I = kg m 2 b) What is the magnitude of the angular momentum about the origin? L= kg m2 /s c)If the length of the rod reduces to l=0.5m. What will be the final angular speed ωf? ωf = rad/s

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