Question

A rod of length l=0.8m and mass M= 3.7kg joins two particles with masses m₁ =4.5kg and m₂ = 2.8kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod with the linear speed of the masses of v= 3.5 m/s. (Moment of inertia of a uniform rod rotating about its center of mass

I=

1

12

M l²

a) Calculate the total moment of inertia of the system

b) What is the magnitude of the angular momentum about the origin?

c)If the length of the rod reduces to l=0.5m. What will be the final angular speed ω_f?

)

Answer 1

I have used I=mR^2 for a pont like mass and for rod I=Ml^2/12, Also conservation of angular momentam is applied for finding final angular velocity.