Question

Given a temperature of 1 eV with an electronic density of 10^23electrons/m^3 for a substance made...

Given a temperature of 1 eV with an electronic density of 10^23electrons/m^3 for a substance made of sodium. Solve for the ratio nNa+/nNa. Use saha equation.

Note: for Na and Na+ at a temperature of 1eV, the internal partition functions are BNa=5.24 and BNa+=1

5.14eV is the ionization potential of sodium.

Science   Advanced-Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Estimate the temperature (in Kelvins) at which GaAs has an electrical conductivity of 4.0 x 10-3...
Estimate the temperature (in Kelvins) at which GaAs has an electrical conductivity of 4.0 x 10-3 (?-m)-1, assuming a temperature dependence for ? as shown in Eq. 18.36. For GaAs, use a band gap of 1.42 eV, and a room temperature (298K) conductivity of 1.0 x 10-6 (?-m)-1.
A density column was made with 3 mL of 1 M calcium chloride solution with a...
A density column was made with 3 mL of 1 M calcium chloride solution with a density of 1.1 g/mL, 3 ml of dyed distilled water with a density of 1.00 g/mL, and then 3 mL of ethanol with a density of 0.80 g/mL. The calcium chloride solution was poured first followed by the distilled water and then ethanol. Why was the calcium chloride solution poured into the density column first?
Given: an atmospheric layer. Height is 5650 m, temperature is -61◦C, pressure is 515 hPa, density...
Given: an atmospheric layer. Height is 5650 m, temperature is -61◦C, pressure is 515 hPa, density is 0.678 kg m−3 , constant vertical velocity of 9.8 cm s−1 . Over 20 minutes, atmospheric flow between the 5650 m and 7745 m surfaces generates layer mean temperature advection of 1.9◦C hr−1 . Calculate the pressure for the 5650 m level after the 20 minutes have passed. With the assumption that atmospheric flow is geostrophic.
The translational partition function of a molecule is given by: qT=(2 π m k T)3/2 (V/h3)....
The translational partition function of a molecule is given by: qT=(2 π m k T)3/2 (V/h3). (Note: m in the equation is the mass of the individual molecule). If V=1 L and T=300 K answer the following question: a) qT for HI at T = 300 K, and V = 1 L. b) qT for HI at T = 2000 K, and V = 1 L.
1) Two elements have photoelectric work functions given by Wn= 570 eV and Wm= 681 eV,...
1) Two elements have photoelectric work functions given by Wn= 570 eV and Wm= 681 eV, respectively. If both metals are illuminated by UV radiation of the same wavelength. Calculate the difference of the maximum kinetic energy of photoelectrons from each surface if wavelength = 298 nm 1.78 x 10^-17 J 111 J 1.34 x 10^-19 J 2.00 x 10^-16 J 2) Two slits have a separation, 6.34 x 10^-2 m. An interference pattern is created 9.71 m away from...
Given: 2.0m diameter steel pipe, density = 2000kg/m^3 and  μ= 10^-2 kg/m*s. What is the fluid power...
Given: 2.0m diameter steel pipe, density = 2000kg/m^3 and  μ= 10^-2 kg/m*s. What is the fluid power required to pump water at 10^5 kg/hr.
You have made measurements at the surface (10 m above the ground) and at 1 km....
You have made measurements at the surface (10 m above the ground) and at 1 km. Surface wind speed was measured as 2 m/s and the wind speed at 1000 m was measured at 9 m/s. Virtual temperature was 303 K at the surface and 292 K at 1000m. The virtual potential temperature at 1000m was 297 K. Calculate the Richardson number for the layer between the serface and 1000m. What does the Richardson number say about stability. Is it...
An infinitely long line of charge has linear charge density 4.00×10^−12 C/m. A proton (mass 1.67×10^−27kg,...
An infinitely long line of charge has linear charge density 4.00×10^−12 C/m. A proton (mass 1.67×10^−27kg, charge +1.60×10^−19 C) is 18.0 cm from the line and moving directly toward the line at 3.80×10^3 m/s. How close does the proton get to the line of charge? Please show all steps CLEARLY so I can follow and understand how to derive the equation and solve for the answer with my given values. Thank you so much in advance!!!
Table 1 shows the temperature-time data were recorded for the reaction between 50.0 mL of 1.18...
Table 1 shows the temperature-time data were recorded for the reaction between 50.0 mL of 1.18 M HA (a weak acid) and 50.0 mL of 0.98 M NH4OH, ammonium hydroxide (a weak base, also known as aqueous ammonia). The solutions were mixed after 60 s of approximately constant temperature readings of 24.20 oC. This is the initial temperature. Table 1: temperature-time Data Time (s) Temperature (oC) Time (s) Temperature (oC) 0 24.25 90 31.22 15 24.22 105 31.12 30 24.20...
A string with a mass density of 3.6 ? 10-3 kg/m is under a tension of...
A string with a mass density of 3.6 ? 10-3 kg/m is under a tension of 370 N and is fixed at both ends. One of its resonance frequencies is 720 Hz. The next higher resonance frequency is 840 Hz. (a) What is the fundamental frequency of this string? ______Hz (b) Which harmonics have the given frequencies? (Enter 1 for the first harmonic, 2 for the second harmonic, etc.) 720 Hz 840 Hz (c) What is the length of the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT