Question

Which should be shorter for the same amount of magnification, a telescope with two converging lenses, or one with a converging lens and a diverging lens?

Answer #1

In **Galilean telescope** (one converging one
diverging lens), it is possible to have a telescopic length lesser
than the f_{o} (focal length of objective lens). The net
length would be around the difference of focal lengths of the two
lenses.

For a **Keplerian telescope** (two converging
lenses), it is not possible to have telescopic length lesser than
the f_{o} (focal length of objective lens). The net length
would be about the sum of the focal lengths of the two lenses.

**Thus, for the same amount of magnification a telescope
with a converging lens and a diverging lens would be shorter than
that of a telescope with two converging lenses.**

Two converging lenses with the focal lengths f 1 = 0.2
m and f2 = 0.4 m are positioned at a distance f1 + f2 to each
other. Such arrangements are called "beam expanders" and are often
used in laser technology
a) What is the expansion ratio W2 / W1?
One of the two converging lenses is now to be replaced
by a diverging lens, with the same expansion ratio W2 / W1 to be
achieved.
b) Which of the...

The focal lengths of the converging and diverging lenses are +15
and -20 cm, respectively. The distance between them is 50 cm and
the object is placed 10 cm to the left of the converging lens.
Determine the location of the final image with respect to the
diverging lens. Is this image real or virtual? Find the total
magnification; is the image inverse or upright?

Two lenses, one converging with focal length 20.0 cm and one
diverging with focal length -11.7 cm , are placed 25.0 cm apart. An
object is placed 60.0 cm in front of the converging lens.
Determine the position of the final image formed.
Express your answer with the appropriate units.
di =
Determine the magnification of the final image formed.
m=

Two lenses, one converging with focal length 21.0 cm and one
diverging with focal length − 12.0 cm , are placed 25.0 cm apart.
An object is placed 60.0 cm in front of the converging lens.
Part A
Find the final image distance from second lens. Follow the sign
conventions.
Express your answer to two significant figures and
Part B
Determine the magnification of the final image formed. Follow
the sign conventions.
Express your answer using two significant figures
include...

One diverging and converging lenses are separated by 12cm. The
first lens on the left is divergent with focal point of 25cm while
the second lens on the right is f=10cm. The object is real and
located 10cm in front of the divergent lens. a) Find the position
of the image due to the first lens, b) Find the final position of
the image, c) calculate the total magnification.

Two lenses, one converging with focal length 20.5 cm and one
diverging with focal length ? 10.5 cm , are placed 25.0?cm apart.
An object is placed 60.0?cm in front of the converging lens.
Part A Find the final image distance from second lens. Follow
the sign conventions. Express your answer to two significant
figures and include the appropriate units. di2 = Part B Determine
the magnification of the final image formed. Follow the sign
conventions. Express your answer using...

An optical system consists of two lenses separated by 35 cm –
first is converging with focal length 10 cm and the second is
diverging with focal length 15 cm. An object is 20 cm to the left
of the first lens. Find the position of the final image using both
a ray diagram and the thin-lens equation. Is the image real or
virtual? Erect or inverted? What is the overall magnification of
the image?

Two lenses are placed 50 cm apart. The first lens is converging
and has a focal length of 20 cm, and the second lens is diverging
and has a focal length of 15 cm. If an object is placed 55 cm in
front of the first lens, where is the final image located? Give
your answer in relation to the second lens. What is the overall
magnification? Is the final image upright or inverted? Is the final
image real or...

An object and two lenses are arranged so that the object is to
the left of and 40cm from a converging lens. The magnitude of the
focal length of the first ens is 25cm. A diverging lens is 100cm to
the right of the first lens and the magnitude of the focal length
is 15cm. Find the location of the final image relative to the
original object, the overall magnification.

Two
lenses are .78m apart and used to form an image. Lens 1 is
converging and has a focal lens of -.42m. lens 2 is diverging and
has a focal point og -0.35m. the object is 2.40m to the left of
lens 1. what is the distance to the final image?

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