Question

An optical system consists of two lenses separated by 35 cm – first is converging with focal length 10 cm and the second is diverging with focal length 15 cm. An object is 20 cm to the left of the first lens. Find the position of the final image using both a ray diagram and the thin-lens equation. Is the image real or virtual? Erect or inverted? What is the overall magnification of the image?

Answer #1

A converging lens, which has a focal length equal to 8.4 cm, is
separated by 30.5 cm from a second lens. The second lens is a
diverging lens that has a focal length equal to -13.7 cm. An object
is 16.8 cm to the left of the first lens.
(a) Find the position of the final image using both a ray
diagram and the thin-lens equation. __________cm to the right of
the object
(b) Is the final image real or...

A converging lens of focal length f1 = +22.5 cm is placed at a
distance d = 60.0 cm to the left of a diverging lens of focal
length f2 = −30.0 cm. An object is placed on the common optical
axis of the two lenses with its base 45.0 cm to the left of the
converging lens. (The thin-lens approximation may be assumed to
hold.) (a) Calculate the location of the final image and its
overall magnification with respect...

Two converging lenses, each having a focal length equal to 10.7
cm, are separated by 38 cm. An object is 21.4 cm to the left of the
first lens.
(a) Find the position of the final image using both a ray
diagram and the thin-lens equation.
cm to the right of the object
(c) What is the overall lateral magnification?

Two lenses are placed 50 cm apart. The first lens is converging
and has a focal length of 20 cm, and the second lens is diverging
and has a focal length of 15 cm. If an object is placed 55 cm in
front of the first lens, where is the final image located? Give
your answer in relation to the second lens. What is the overall
magnification? Is the final image upright or inverted? Is the final
image real or...

1. A converging lens has a focal length of 14 cm. An object is
18 cm to the left of the lens.
Find the image position
The magnification
Real or virtual?
Erect of inverted?
e. Draw the ray diagram using principal rays and a ruler.
f. If the object was located 7 cm to the left of the lens, draw
the ray diagram.

Two thin lenses with a focal length of magnitude 10.0 cm , the
first diverging and the second converging, are located 7.50 cm
apart. An object 3.00 mm tall is placed 16.7 cm to the left of the
first (diverging) lens.
How far from this first lens is the final image formed?
Is the final image real or virtual?
What is the height of the final image?
Is it upright or inverted?
Thank you!!

Two thin lenses with a focal length of magnitude 11.5 cm, the
first diverging and the second converging, are located 8.62 cm
apart. An object 1.90 mm tall is placed 19.2 cm to the left of the
first (diverging) lens.
A. How far from the first lens is the final image formed?
B. Is the final image virtual or real?
C. What is the height of the final image?
D. Is it upright or inverted?

Two thin lenses with a focal length of magnitude 11.0 cm, the
first diverging and the second converging, are located 8.25 cm
apart. An object 1.60 mm tall is placed 18.3 cm to the left of the
first (diverging) lens. Part A How far from this
first lens is the final image formed? Part B Is
the final image real or virtual? Part C What is
the height of the final image? Part D Is it
upright or inverted?

Two converging lenses, the first with focal length f1 = 25 cm
and the second with focal length f2 = 15 cm are separated by a
distance of ` = 65 cm. An object is place at a distance of do1 = 45
cm to the left of the first lens.
(a) What will be the distance from the second lens that the final
image is produced? Is this image to the left or right of the second
lens? Justify...

One diverging and converging lenses are separated by 12cm. The
first lens on the left is divergent with focal point of 25cm while
the second lens on the right is f=10cm. The object is real and
located 10cm in front of the divergent lens. a) Find the position
of the image due to the first lens, b) Find the final position of
the image, c) calculate the total magnification.

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