Question

A snowball has a of mass 40 g at starting temp of −10◦C and then placed into a glass beaker with with 150 g of water at a temperature of  20◦C, . Mass of the 75 g is the mass of the empty glass beaker

Calculate final temperature of the system and if there is ice from the snowball left over

Answer 1

Solution: Mass of ice (M1)= 40g

Mass of water = Total mass of glass with water - Mass of empty glass

Mass of water(M2) = 150-75 = 75g

We will use heat pool theory in which we will take the system to zero degree temp water and then we will calculate in which direction this system will move.

If the final energy will be positive then the temp will rise and if it will be negative then we will find how much of it will get converted into ice and how much will remain as water at zero degree.

H= -(L_{​​​​​​f} × M1) + (s_{​​​​​​i} ×M1 × T) + (s_{​​​​​​w} ×M2 × T)

H = -(334 × 40) + (2.04 × 40×10) +(4.18 × 75 × 20)

H= -1336+816+6270

H= 5750J

As we have this positive so the whole system temp will rise from this zero degree temp.

H= M × s_{​​​​​​w} × T

5750 = 115 × 4.18 × T

T= 11.96

So the final temp of this whole system will 11.96 °C