Question

A copper cylinder with a mass of 125 g and temperature of 345°C is cooled by dropping it into a glass beaker containing 565 g of water initially at 20.0°C. The mass of the beaker is 50.0 g and the specific heat of the glass is 840 J/kg∙K. What is the final equilibrium temperature of the system, assuming the cooling takes place very quickly, so that no energy is lost to the air? The specific heat of copper is 385 J/kg∙K and that of water is 4190 J/kg∙K.

Answer #1

Let the equilibrium temperature be T oC.

Now

Heat lost by Copper Cylinder = Heat gained by water + heat gained by the glass beaker.

Now heat gain or loss is given by the formula mxCpxdeltaT

Where m is the mass; Cp is the specific heat; delta T is the temperature change.

(0.125 kg)x(385 J/kg-K)x(345 - T) = (0.565 kg)x(4190 J/kg-K)x(T - 20) + (0.050 kg)x(840 J/kg-K)x(T - 20).

16603.125 + 48.125T = 2367.35T - 47347 + 42T - 840

64790.125 = 2361.225T

T = 27.44 ^{o}C.

Please Show all work, thank you!
A copper block with a mass of 400 grams is cooled to 77 K by
being immersed in liquid nitrogen. The block is then placed in a
Styrofoam cup containing some water that is initially at +50.0°C.
Assume no heat is transferred to the cup or the surroundings. The
specific heat of liquid water is 4186 J/(kg °C), of solid water is
2060 J/(kg °C), and of copper is 385 J/(kg °C). The latent...

A copper block is removed from a 320 ∘C oven and dropped into
1.20 kg of water at 22.0 ∘C. The water quickly reaches 27.5 ∘C∘and
then remains at that temperature.
What is the mass of the copper block? The specific heats of
copper and water are 385 J/(kg⋅K) and 4190 J/(kg⋅K) respectively.
Express your answer with the appropriate units.

52.76 g of copper pellets are removed from a 333°C
oven and immediately dropped into 151 mL of water at
16°C in an insulated cup. What will the new water
temperature be?
Specific heat of the copper is 385 J/kg·°C, specific
heat of the water is 4190 J/kg·°C.

An insulated beaker with negligible mass contains liquid water
with a mass of 0.235 kg and a temperature of 68.6 ∘C .
How much ice at a temperature of -20.0 ∘C must be dropped into
the water so that the final temperature of the system will be 25.0
∘C ?
Take the specific heat of liquid water to be 4190 J/kg⋅K , the
specific heat of ice to be 2100 J/kg⋅K , and the heat of fusion for
water to...

An insulated beaker with negligible mass contains liquid water
with a mass of 0.235 kg and a temperature of 66.5 ∘C .
How much ice at a temperature of -18.4 ∘C must be dropped into
the water so that the final temperature of the system will be 20.0
∘C ?
Take the specific heat of liquid water to be 4190 J/kg⋅K , the
specific heat of ice to be 2100 J/kg⋅K , and the heat of fusion for
water to...

Hot tea (water) of mass 0.21 kg and temperature 62 ∘C is
contained in a glass of mass 200 g that is initially at the same
temperature. You cool the tea by dropping in ice cubes out of the
freezer that are at a temperature of – 11 ∘C. What is the minimum
amount of ice in you need to make ice tea (final temperature of
0∘C)? Give your answer in kg to two decimal places. The specific
heat of...

An insulated beaker with negligible mass contains liquid water
with a mass of 0.230 kg and a temperature of 72.0 ∘C .
Part A
How much ice at a temperature of -13.8 ∘C must be dropped into
the water so that the final temperature of the system will be 20.0
∘C ?
Take the specific heat of liquid water to be 4190 J/kg⋅K , the
specific heat of ice to be 2100 J/kg⋅K , and the heat of fusion for...

A 24 g block of ice is cooled to −63◦C. It is added
to 572 g of water in a 98 g copper calorimeter at a temperature of
30◦C.
Find the final temperature. The specific heat of copper is 387
J/kg ·◦C and of ice is 2090 J/kg ·◦C. The
latent heat of fusion of water is 3.33 × 105 J/kg and its specific
heat is 4186 J/kg·◦C.
Answer in units of ◦C.

A 31 g block of ice is cooled to −90◦C. It is added to 591 g of
water in an 65 g copper calorimeter at a temperature of 26◦C. Find
the final temperature. The specific heat of copper is 387 J/kg · ◦C
and of ice is 2090 J/kg · ◦C . The latent heat of fusion of water
is 3.33 × 105 J/kg and its specific heat is 4186 J/kg · ◦C . Answer
in units of ◦C.

In a copper vessel with a temperature of t1 = 350 C, m2 = 600 g
of ice
with a temperature of t1 = 10 C. After some time a
Mixture of m3 = 550 g ice and m4 = 50 g water. Find the mass of the
vessel m1.
In the solution, neglect the heat exchange between the vessel
and
environment.
The specific heat capacity of copper is cK = 0:39 kJ/(kg*K). The
specific
Heat capacity of the ice...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 6 minutes ago

asked 26 minutes ago

asked 47 minutes ago

asked 47 minutes ago

asked 50 minutes ago

asked 55 minutes ago

asked 57 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago