Question

Mass of Ca(s) 0.5 g volume of water 50.0 mL initial temp 25.6 C final temp...

Mass of Ca(s) 0.5 g
volume of water 50.0 mL
initial temp 25.6 C
final temp 48.5 C

calculate the enthalpy of dissolution of Ca in water in kJ/mol

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Answer #1

Given data:

The mass of Ca(s) (m) = 0.5 g, its no. of moles (n) = 0.5 g / 40 g mol-1, i.e. 0.0125 mol

The volume of water = 50 mL

Therefore, the concentration of Ca in water = (0.0125 mol / 50 L) * 1000 = 0.25 mol/L

The change in temperature (T) = 48.5 - 25.6 = 22.9 oC = (22.9 + 273.15) K = 296.05 K

The heat required for calcium (q) = (c)Ca * m * T

= 0.647 J/g•K * 0.5 g * 296.05 K

= 95.77 J

Therefore, the enthapy of dissolution of Ca in water = q/n

= 95.77 J / 0.0125 mol

= 7.66 KJ/mol

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