Question

A glass thermometer (m = 13.0 g) is placed into a 110 g cup filled with 220 g of water. These objects have an initial temperature of 28°C. Pieces of ice with a mass of 49 g and starting at -5° is dropped into the cup and water. The equilibrium temperature of the system is 9°C.

Find the specific heat of the cup.

What is the closest material to this value?

Answer 1

here,

the mass of thermometer , m1 = 13 g

the mass of cup , m2 = 110 g

the mass of water , m3 = 220 g

mass of ice , m4 = 49 g

the equilibrium temperature , Tf = 9 degree C

using principle of calorimetry

m1 * Cg * (28 - Tf) + m2 * Cc * ( 28 - Tf) + m3 * Cw * (28 - Tf) = m4 * ( Ci *( 0 - (-5)) + Lf + Cw * ( Tf - 0))

13 * 0.84 * (28 - 9) + 110 * Cc * ( 28 - 9) + 220 * 4.186 * (28 - 9) = 49 * ( 2 *( 0 - (-5)) + 333.7 + 4.186 * (9 - 0))

solving for Cc

Cc = 0.470 J/(g. K)

the specific heat of glass is 0.470 J/(g. K)

the substance is Steel