Question

Ice of mass 46.5 g at -10.5° C is added to 214 g of water at
14.4° C in a 110 g glass container of specific heat 0.200 cal/g-°C
at an initial temperature of 23.7° C. Find the final temperature of
the system.

°C

Answer #1

heat enegry required to melt ice completley,

Q1=m_ice*C_ice*dT + m_ice*L_ice

= 46.5*2.03*(10.5) + 46.5*334

= 16522.15 J ----(1)

heat energy released by the water and container to reach 0 oC

Q2=m_water*C_water*dT + m_container*C_container*dT

Q2 = 214*4.18*14.4 + 110*0.837*23.7

Q2= 15063.15 J ----(2)

from equation no (1) and (2),

heat enegry required to melt ice completley is greater than the
heat energy released by the water and container to reach 0 oC

hence, final temperature of the system will be **0
oC**

Ice of mass 52.5 g at -10.7° C is added to 220 g of water at
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A 40-g block of ice is cooled to
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Determine the final temperature of the system consisting of the
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Determine the final temperature of the system consisting of the
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Given: Initial tea temp is 65 degrees C, Initial weight of tea
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