Question

Ice of mass 46.5 g at -10.5° C is added to 214 g of water at...

Ice of mass 46.5 g at -10.5° C is added to 214 g of water at 14.4° C in a 110 g glass container of specific heat 0.200 cal/g-°C at an initial temperature of 23.7° C. Find the final temperature of the system.
°C

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Answer #1

heat enegry required to melt ice completley,


Q1=m_ice*C_ice*dT + m_ice*L_ice


= 46.5*2.03*(10.5) + 46.5*334


= 16522.15 J    ----(1)

heat energy released by the water and container to reach 0 oC


Q2=m_water*C_water*dT + m_container*C_container*dT


Q2 = 214*4.18*14.4 + 110*0.837*23.7


Q2= 15063.15 J   ----(2)

from equation no (1) and (2),


heat enegry required to melt ice completley is greater than the heat energy released by the water and container to reach 0 oC


hence, final temperature of the system will be 0 oC

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