Question

4. A box sits on an inclined plane without sliding. As the angle of inclination increases,...

4. A box sits on an inclined plane without sliding. As the angle of inclination increases, thenormal force
(a) decreases(b) increases(c) does not change(d) is directed upward

please explain why.

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

MgSin =

As increases, Sin increases, For equation to hold true, N decreases,   <90

MgCos = N

Similarly As increases , Cos decreases, N decreases   <90

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 5 kg box sits on an inclined plane. If the coefficient of static friction between...
A 5 kg box sits on an inclined plane. If the coefficient of static friction between the plane and the box is µs = 0.15. What is the maximum angle θmax that the plane can be inclined without the box sliding?
A 16.1 kg box is at rest on an inclined plane. The plane makes an angle...
A 16.1 kg box is at rest on an inclined plane. The plane makes an angle of 39.3 with the horizontal. How much is the friction force (in Newtons) on the plane that holds it at rest?
A box is on an inclined which has angle θ=30 degrees with horizon. There is a...
A box is on an inclined which has angle θ=30 degrees with horizon. There is a box with mass M=5 kg on the inclined. The coefficient of friction between the box and the surface of inclined is μ=0.2 . a) If the box is kicked to move up the inclined and start moving up with velocity V=15 m/s moving upward, how far d=? does It move along the surface of inclined? b) How much energy Q=? is lost while the...
A box is sliding down an incline tilted at a 11.8° angle above horizontal. The box...
A box is sliding down an incline tilted at a 11.8° angle above horizontal. The box is initially sliding down the incline at a speed of 1.60 m/s. The coefficient of kinetic friction between the box and the incline is 0.390. How far does the box slide down the incline before coming to rest? A) .736 m B) 1.03 m C) .883 m D) .589 m E) the box does not stop. it accelerates down the plane.
In the figure, a 5.40 kg block is sent sliding up a plane inclined at θ...
In the figure, a 5.40 kg block is sent sliding up a plane inclined at θ = 37.0° while a horizontal force   of magnitude 50.0 N acts on it. The coefficient of kinetic friction between block and plane is 0.330. What are the (a) magnitude and (b) direction (up or down the plane) of the block's acceleration? The block's initial speed is 4.30 m/s. (c) How far up the plane does the block go? (d) When it reaches its highest...
1a.  a box of dirty money (mass m1 = 3.5 kg) on a frictionless plane inclined at...
1a.  a box of dirty money (mass m1 = 3.5 kg) on a frictionless plane inclined at angle θ1 = 37°. The box is connected via a cord of negligible mass to a box of laundered money (mass m2 = 1.3 kg) on a frictionless plane inclined at angle θ2 = 54°. The pulley is frictionless and has negligible mass. What is the tension in the cord? 1b. three blocks attached by cords that loop over frictionless pulleys. Block B lies...
A block of weight w = 25.0 N sits on a frictionless inclined plane, which makes...
A block of weight w = 25.0 N sits on a frictionless inclined plane, which makes an angle θ = 20.0 ∘ with respect to the horizontal, as shown in the figure. (Figure 1)A force of magnitude F = 8.55 N , applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed. Part B What is Wg, the work done on the block by the force of gravity w⃗  as the block moves...
A 4.08 kg box begins to slide from rest through a plane inclined at 25.0 degrees...
A 4.08 kg box begins to slide from rest through a plane inclined at 25.0 degrees (with respect to the horizontal) and which is 7.00 m long. The friction force between the box and the inclined plane is 5.0 N. Determine: (a) the speed of the box when reaching the end of the inclined plane (using what was learned in work / energy): Answer Answer (b) the coefficient of kinetic friction: Answer Answer Please answer as quick as possible! I...
A 4.08 kg box begins to slide from rest through a plane inclined at 25.0 degrees...
A 4.08 kg box begins to slide from rest through a plane inclined at 25.0 degrees (with respect to the horizontal) and which is 7.00 m long. The friction force between the box and the inclined plane is 5.0 N. (explain each process and how you got to the answer) Determine: (a) the speed of the box when reaching the end of the inclined plane (using what was learned in work / energy): Answer (b) the coefficient of kinetic friction:...
A block of weight w = 30.0 N sits on a frictionless inclined plane, which makes...
A block of weight w = 30.0 N sits on a frictionless inclined plane, which makes an angle θ = 35.0 ∘ with respect to the horizontal, as shown in the figure. (Figure 1) A force of magnitude F = 17.2 N , applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed. PLEASE PUT ALL ANSWERS IN JOULES Part A The block moves up an incline with constant speed. What is...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT