Question

In the figure, a 5.40 kg block is sent sliding up a plane
inclined at *θ* = 37.0° while a horizontal force
of magnitude 50.0 N acts on it. The coefficient of
kinetic friction between block and plane is 0.330. What are the
**(a)** magnitude and **(b)** direction
(up or down the plane) of the block's acceleration? The block's
initial speed is 4.30 m/s. **(c)** How far up the
plane does the block go? **(d)** When it reaches its
highest point, does it remain at rest or slide back down the
plane?

Answer #1

Hope this help you.

Please thumbs up.

A 4.25 kg block is projected at 5.40 m/s up a plane that is
inclined at 30.0° with the horizontal. The block slides some
distance up the incline, stops turns around and slides back down to
the bottom. When it reaches the bottom of the incline again, it is
traveling with a speed of 3.80 m/s. If the coefficient of kinetic
friction between the block and the plane is 0.500, how far up the
incline did the block slide?

A 4.25 kg block is projected at 5.40 m/s up a plane that is
inclined at 30.0° with the horizontal. The block slides some
distance up the incline, stops turns around and slides back down to
the bottom. When it reaches the bottom of the incline again, it is
traveling with a speed of 3.80 m/s. If the coefficient of kinetic
friction between the block and the plane is 0.500, how far up the
incline did the block slide? Please...

A
10 kg block is launched up a plane inclined at a 15° angle. The
initial speed of the block is 5 m/s.
a) Using Newton's laws of motion and the equations of
kinematics, calculate how far up the inclined plane does the block
slide in the absence of friction?
b) Using work and energy, answer the question in part (a) in
the presence of friction, taking the coefficient of kinetic
friction between the block and the surface to be...

A block of mass m = 14.5 kg rests on an inclined plane
with a coefficient of static friction of μs =
0.16 between the block and the plane. The inclined plane is
L = 6.1 m long and it has a height of h = 3.8 m
at its tallest point.
A.What angle, θ in degrees, does the plane make with
respect to the horizontal?
B.What is the magnitude of the normal force,
FN in newtons, that acts on...

A 3.00 kg block slides down a 37.0 degree inclined plane. If the
acceleration of the block is 1.52 m/s2, a) the force of kinetic
friction on the block. b) the normal force on the block. c) the
coefficient of kinetic friction on the block. d) the angle needed
to make the block slide down the incline at a constant speed.

A 5.00-kg5.00-kg block is sent up a ramp inclined at an angle
?=28.0∘θ=28.0∘ from the horizontal. It is given an initial velocity
?0=15.0 m/sv0=15.0 m/s up the ramp. Between the block and the ramp,
the coefficient of kinetic friction is ?k=0.50μk=0.50 and the
coefficient of static friction is ?s=0.60.μs=0.60.
What distance ?D along the ramp's surface does the block travel
before it comes to a stop?

A 5.00-kg 5.00-kg block is sent up a ramp inclined at an angle
?= 25.0 ∘ θ=25.0∘ from the horizontal. It is given an initial
velocity ? 0 =15.0 m/s v0=15.0 m/s up the ramp. Between the block
and the ramp, the coefficient of kinetic friction is ? k =0.50
μk=0.50 and the coefficient of static friction is ? s =0.60.
μs=0.60. What distance ? D along the ramp's surface does the block
travel before it comes to a stop?

A block is at rest on an inclined plane whose elevation can be
varied. The coefficient of static friction is
μs= 0.36, and the coefficient of kinetic
friction is μk = 0.16. The angle of elevation θ
is increased slowly from the horizontal.
At what value of θ does the block begin to slide (in
degrees)?
What is the acceleration of the block?

A 3.00-kg block is sent up a ramp of angle θ equal to 43.0° with
an initial velocity ν0 equal to 23.0 m/s. Between the block and the
ramp, the coeffiient of kinetic friction is μk equal to 0.50 and
the coefficient of static friction is μs equal to 0.80. 1) How far
up the ramp (in the direction along the ramp) does the block go
before it comes to a stop? (Express your answer to two significant
figures.)

A block of mass m = 3.3 kg is on an inclined plane with
a coefficient of friction μ1 = 0.39, at an
initial height h = 0.53 m above the ground. The plane is
inclined at an angle θ = 44°. The block is then compressed
against a spring a distance Δx = 0.13 m from its
equilibrium point (the spring has a spring constant of
k1 = 35 N/m) and released. At the bottom of the
inclined plane...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 14 minutes ago

asked 39 minutes ago

asked 39 minutes ago

asked 44 minutes ago

asked 52 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago