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A 4.08 kg box begins to slide from rest through a plane inclined at 25.0 degrees...

A 4.08 kg box begins to slide from rest through a plane inclined at 25.0 degrees (with respect to the horizontal) and which is 7.00 m long. The friction force between the box and the inclined plane is 5.0 N. (explain each process and how you got to the answer)

Determine:

(a) the speed of the box when reaching the end of the inclined plane (using what was learned in work / energy): Answer

(b) the coefficient of kinetic friction: Answer

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