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A 16.1 kg box is at rest on an inclined plane. The plane makes an angle...

A 16.1 kg box is at rest on an inclined plane. The plane makes an angle of 39.3 with the horizontal. How much is the friction force (in Newtons) on the plane that holds it at rest?

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Answer #1

Given data:

Mass of block = 16.1 Kg

Angle of inclination = 39.3o

Concept: By making Free body diagram of Block, we will calculate the fore of friction, that hold the block in rest position on inclined surface.

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