Question

A 5 kg box sits on an inclined plane. If the coefficient of static friction between the plane and the box is µs = 0.15. What is the maximum angle θmax that the plane can be inclined without the box sliding?

Answer #1

Given:- m = 5kg ,µs = 0.15

maximum friction (f)= uN

N = mgcos()

component of mg along inclined plane is mgsin()

By Newton’s second law:-

f = umgcos() = mgsin()

tan() = u = 0.15

= 8.54 degree

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