Question

Given: G = 6.67259 × 10−11 N · m2 /kg2 A satellite moves in a circular orbit around Earth at a speed of 3650 m/s. Find the satellite’s altitude above the surface of Earth. Answer in units of m. 015 (part 2 of 2) 10.0 points Find the period of the satellite’s orbit. Answer in units of h

Answer #1

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(part 1 of 3) A satellite of mass 398 kg is launched from a site
on the Equator into an orbit at 544 km above Earth’s surface. If
the orbit is circular, what is the satellite’s speed in orbit? The
gravitational constant is 6.67259 × 10^−11 N · m2/kg2 , the mass of
the earth is 5.98 × 10^24 kg and its radius is 6.37 × 10^6 m.
Answer in units of m/s.
(part 2 of 3) What is the...

A GPS satellite moves around Earth in a circular orbit with
period 11 h 58 min. Determine the radius of its orbit. Hint: use
the Newton’s 2nd law of motion relating the gravitational force and
the centripetal acceleration of the satellite. Assume the following
is given: Earth’s mass MEarth = 6x10^24 kg, Earth’s radius REarth =
6.378x10^6 m, and the gravitational constant G = 6.67x10^-11
Nm2/kg2.

A satellite is in a circular orbit around the Earth at an
altitude of 3.78 106 m.(Hint: Solve the parts in reverse order.)
(a) Find the period of the orbit. h (b) Find the speed of the
satellite. (c) Find the acceleration of the satellite. m/s2 toward
the center of the earth

A satellite is in a circular orbit around the Earth at an
altitude of 3.32 106 m. (a) Find the period of the orbit. (Hint:
Modify Kepler's third law so it is suitable for objects orbiting
the Earth rather than the Sun. The radius of the Earth is 6.38 106
m, and the mass of the Earth is 5.98 1024 kg.) h (b) Find the speed
of the satellite. km/s (c) Find the acceleration of the satellite.
m/s2 toward the...

A satellite is in a circular orbit around the Earth at an
altitude of 3.84 106 m.
(a) Find the period of the orbit. (Hint: Modify
Kepler's third law so it is suitable for objects orbiting the Earth
rather than the Sun. The radius of the Earth is
6.38 106 m, and the mass of the Earth is
5.98 1024 kg.)
h
(b) Find the speed of the satellite.
km/s
(c) Find the acceleration of the satellite.
m/s2 toward the center of the...

A satellite is in circular orbit at an altitude of 1800 km above
the surface of a nonrotating planet with an orbital speed of 3.7
km/s. The minimum speed needed to escape from the surface of the
planet is 8.4 km/s, and G = 6.67 × 10-11 N ·
m2/kg2. The orbital period of the satellite
is closest to
59 min.
83 min.
75 min.
67 min.
51 min.

A satellite of mass 1525 kg is in circular orbit around Earth.
The radius of the orbit of the satellite is equal to 1.5 times the
radius of Earth (RE = 6.378*106 m, ME = 5.98*1024 kg, G =
6.67*10-11 Nm2/kg2). (a) Find the orbital period of the satellite?
(b) Find the orbital (tangential) velocity of the
satellite. (c) Find the total energy of the
satellite?

A satellite is in circular orbit at an altitude of 1500 km above
the surface of a nonrotating planet with an orbital speed of 3.4
km/s. The minimum speed needed to escape from the surface of the
planet is 8 km/s, and G = 6.67 × 10-11 N ·
m2/kg2. The orbital period of the satellite
is closest to
A)59 min.
B)45 min.
C)72 min.
D)65 min.
E)52 min.

Scientists want to place a 1000 kg satellite in a circular orbit
around Venus. They want the height of the orbit to be three times
the radius of Venus. Mvenus = 4.867 x 1024 kg Rvenus = 6.050 x 106
m G = 6.67428 x 10-11 N-m2/kg2
A) What would be the force of gravity between Venus and the
satellite?
B) What would be the acceleration due to gravity at the
satellite’s orbit?
C) What would be the orbital speed...

A satellite is in a circular orbit around the Earth at an
altitude of 1.66 106 m. (a) Find the period of the orbit (in hrs).
(Hint: Modify Kepler's third law: T2 = (4π2/GMS)r3 so it is
suitable for objects orbiting the Earth rather than the Sun. The
radius of the Earth is 6.38 106 m, and the mass of the Earth is
5.98 1024 kg.) (b) Find the speed of the satellite (in km/s). (c)
Find the acceleration of...

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