Question

A satellite is in circular orbit at an altitude of 1500 km above
the surface of a nonrotating planet with an orbital speed of 3.4
km/s. The minimum speed needed to escape from the surface of the
planet is 8 km/s, and G = 6.67 × 10^{-11} N ·
m^{2}/kg^{2}. The orbital period of the satellite
is closest to

A)59 min. |

B)45 min. |

C)72 min. |

D)65 min. |

E)52 min. |

Answer #1

The answer for above problem is explained below.

A satellite is in circular orbit at an altitude of 1800 km above
the surface of a nonrotating planet with an orbital speed of 3.7
km/s. The minimum speed needed to escape from the surface of the
planet is 8.4 km/s, and G = 6.67 × 10-11 N ·
m2/kg2. The orbital period of the satellite
is closest to
59 min.
83 min.
75 min.
67 min.
51 min.

a) For a satellite to be in a circular orbit 850 km above the
surface of the earth, what orbital speed must it be given?
b) What is the period of the orbit (in hours)?

A 400 kg satellite is in a circular orbit at an altitude of 550
km above the Earth's surface. Because of air friction, the
satellite eventually falls to the Earth's surface, where it hits
the ground with a speed of 1.90 km/s. How much energy was
transformed into internal energy by means of air friction?
J

A satellite is set to orbit at an altitude of 20200 km above the
Earth's surface. What is the period of the satellite in hours?
(Earth radius 6.378×1066.378×106 m, Earth mass 5.97×10245.97×1024
kg, Universal Gravitational constant
G=6.67×10−11m3kg−1s−2G=6.67×10−11m3kg−1s−2 ).

A 160 kg satellite is orbiting on a circular orbit 7655 km above
the Earth's surface. Determine the speed of the satellite. (The
mass of the Earth is 5.97×1024
kg, and the radius of the Earth is 6370 km.)
(in km/s)

The orbital period of a satellite is 1 hr 34 min. It orbits at
an altitude of 480 km above the Earth's surface.
a) Determine the initial velocity in order to launch the
satellite in that circular orbit.
b) Find the speed of the satellite once its circular orbit has
been achieved. Assume a uniform circular motion.

An Earth satellite is in a circular orbit at an altitude of 500
km. Explain why the work done by the gravitational force acting on
the satellite is zero. Using the work-energy theorem, what can you
say about the speed of the satellite?

A. At what altitude above the Earth's surface would a satellite
have to be for it’s orbital period to be equal to 24 hours? Assume
the satellite is in a circular orbit. Assume a spherical, uniform
density for the Earth. The Earth's mass 5.98 x 10 raised to 24kg.
The Earth's radius is 6380 km B. Why would a satellite in such an
orbit be a useful thing?

What velocity is needed to launch a satellite into a circular
orbit at an altitude of 800 km above the surface of the Earth?

Two satellites are in circular orbits around the earth. The
orbit for satellite A is at a height of 406 km above the earth's
surface, while that for satellite B is at a height of 904 km. Find
the orbital speed for satellite A and satellite B.

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