Question

A satellite is in circular orbit at an altitude of 1800 km above
the surface of a nonrotating planet with an orbital speed of 3.7
km/s. The minimum speed needed to escape from the surface of the
planet is 8.4 km/s, and G = 6.67 × 10^{-11} N ·
m^{2}/kg^{2}. The orbital period of the satellite
is closest to

59 min. |

83 min. |

75 min. |

67 min. |

51 min. |

Answer #1

A satellite is in circular orbit at an altitude of 1500 km above
the surface of a nonrotating planet with an orbital speed of 3.4
km/s. The minimum speed needed to escape from the surface of the
planet is 8 km/s, and G = 6.67 × 10-11 N ·
m2/kg2. The orbital period of the satellite
is closest to
A)59 min.
B)45 min.
C)72 min.
D)65 min.
E)52 min.

a) For a satellite to be in a circular orbit 850 km above the
surface of the earth, what orbital speed must it be given?
b) What is the period of the orbit (in hours)?

A 400 kg satellite is in a circular orbit at an altitude of 525 km
above the Earth's surface. Because of air friction, the satellite
eventually falls to the Earth's surface, where it hits the ground
with a speed of 2.30 km/s. How much energy was transformed into
internal energy by means of air friction?

A 4,000 kg satellite is traveling in a circular orbit 200 km
above the surface of the Earth. A 30.0 gram marble is dropped
inside the satellite. What is the force of gravity on the marble as
viewed by the observers on the Earth? (ME = 5.98 ×
1024 kg, RE = 6.37 × 106 m, G =
6.67 × 10−11 N·m2/kg2)
A 5,000 kg satellite is orbiting the Earth in a circular path.
The height of the satellite above...

A 400 kg satellite is in a circular orbit at an altitude of 550
km above the Earth's surface. Because of air friction, the
satellite eventually falls to the Earth's surface, where it hits
the ground with a speed of 1.90 km/s. How much energy was
transformed into internal energy by means of air friction?
J

Satellite to be in a circular orbit 590 km above the surface of
the earth.
a?) What orbital speed must it be given?
b) What is the period of the orbit (in hours)?
Express your answer in hours

A satellite is set to orbit at an altitude of 20200 km above the
Earth's surface. What is the period of the satellite in hours?
(Earth radius 6.378×1066.378×106 m, Earth mass 5.97×10245.97×1024
kg, Universal Gravitational constant
G=6.67×10−11m3kg−1s−2G=6.67×10−11m3kg−1s−2 ).

An artificial satellite is in a circular orbit d=730.0 km above
the surface of a planet of radius r=2.75×103 km. The
period of revolution of the satellite around the planet is T=3.15
hours. What is the average density of the planet?

A 160 kg satellite is orbiting on a circular orbit 7655 km above
the Earth's surface. Determine the speed of the satellite. (The
mass of the Earth is 5.97×1024
kg, and the radius of the Earth is 6370 km.)
(in km/s)

The orbital period of a satellite is 1 hr 34 min. It orbits at
an altitude of 480 km above the Earth's surface.
a) Determine the initial velocity in order to launch the
satellite in that circular orbit.
b) Find the speed of the satellite once its circular orbit has
been achieved. Assume a uniform circular motion.

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