Suppose that f(2) = −3, g(2) = 4, f '(2) = −1, and g'(2) = 5. Find h'(2). (a) h(x) = 3f(x) − 5g(x) h'(2) h(x) = f(x)g(x) h'(2) = h(x) = f(x) g(x) h'(2) =(d) h(x) = g(x) 1 + f(x) h'(2) =
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