Question

Suppose the opcode of an MIPS instruction is 0 in decimal, the funct is 011000 in...

Suppose the opcode of an MIPS instruction is 0 in decimal, the funct is 011000 in binary, and the rest of the machine code is c4000 in hexadecimal (from high-order bit to low-order bit). What is the instruction? When showing the registers, use names (e.g. $t0, $s2) instead of indices (e.g $8, $17).

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Answer #1 
Hexadecimal     Binary
    0           0000
    1           0001
    2           0010
    3           0011
    4           0100
    5           0101
    6           0110
    7           0111
    8           1000
    9           1001
    A           1010
    B           1011
    C           1100
    D           1101
    E           1110
    F           1111
Use this table to convert from hexadecimal to binary
Converting C4000 to binary
C => 1100
4 => 0100
0 => 0000
0 => 0000
0 => 0000
So, in binary C4000 is 11000100000000000000

opcode = 000000
rest = 11000100000000000000
funct = 011000 (mult)

=>  00000011000100000000000000011000
=>  000000 11000  10000  0000000000 011000
=>  SPECIAL    $t8    $s0    0  MULT
=>  SPECIAL    rs rt 0  MULT
so, instruction is mult $t8, $s0

Answer:
--------
mult $t8, $s0
0 0
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