Question

A.6

...

static int x = 1;

int y = x * 2;

void t1() {

                y++;

                cout << "x: " << x << " | y: " << y << endl;

                y += 1;

                x -= -1;

}

void t2() {

                int* x = &y;

                cout << "x: " << x << " | y: " << y << endl;

}

void t3() {

                int y = x;

                static int x = 2;

                cout << "x: " << x + 1 << " | y: " << y + x << endl;

                x += y;

}

void t4() {

                int y = x + 1;

                int& z = y;

                z += -1;

                cout << "x: " << x + z << " | y: " << y << endl;

}

int main() {

                vector<int> vec1{ 1, 3, 5, 7, 9 };

                vector<int> vec2{ 2, 4, 6, 8, 10 };

                vec1.swap(vec2);

                int * ptr = &vec1[1];

                y = *(ptr + 2);

                t1();

                t2();

                t3();

                t3();

                t4();

                return 0;

}

This program outputs 5 lines. What are they?

1.

2.

3.

4.

5.

A.7 - 15 Points

int x = 1, y = -1;

void swapplus1(int n1, int n2) {

                int temp = n1 + 1;

                n1 = n2 - 1;

                n2 = temp;

                x = x + n1;

}

void swapplus2(int& n1, int& n2) {

                int temp = n1 + 1;

                n1 = n2 - 1;

                n2 = temp;

}

void swapplus3(const int& n1, const int& n2) {

                int n1val, n2val, temp = n1 + 1;

                n1val = n2 - 1;

                n2val = temp;

                y -= n2;

}

void swapplus4(int* p1, int* p2) {

                int temp = *p1 + 1;

                *p1 = *p2 + 1;

                *p2 = temp;

                x = *p1 + y;

}

void swapplus5(int* &p1, int* &p2) {

                int* temp = p1 + 1;

                p1 = p2 - 1;

                p2 = temp;

}

void print(const int& x, const int& y) {

                cout << "\n x: " << x << " |y: " << y;

}

int main() {

                int arr[]{ 2, 4, 6, 8, 10, 12, 14 };

                y = arr[3] / size(arr) ;

                swapplus1(x, y);      print(x, y);

                swapplus2(x, y);      print(x, y);

                swapplus3(x, y);      print(x, y);

                swapplus4(&x, &y); print(x, y);

                int *px = &x, *py = &y;

                (*px)--;

                (*py) -= -7;

                swapplus5(px, py); print(x, y);

                return 0;

}

This program outputs 5 lines. What are they?

1.

2.

3.

4.

5.

A.7

int x = 1, y = -1;

void swapplus1(int n1, int n2) {

                int temp = n1 + 1;

                n1 = n2 - 1;

                n2 = temp;

                x = x + n1;

}

void swapplus2(int& n1, int& n2) {

                int temp = n1 + 1;

                n1 = n2 - 1;

                n2 = temp;

}

void swapplus3(const int& n1, const int& n2) {

                int n1val, n2val, temp = n1 + 1;

                n1val = n2 - 1;

                n2val = temp;

                y -= n2;

}

void swapplus4(int* p1, int* p2) {

                int temp = *p1 + 1;

                *p1 = *p2 + 1;

                *p2 = temp;

                x = *p1 + y;

}

void swapplus5(int* &p1, int* &p2) {

                int* temp = p1 + 1;

                p1 = p2 - 1;

                p2 = temp;

}

void print(const int& x, const int& y) {

                cout << "\n x: " << x << " |y: " << y;

}

int main() {

                int arr[]{ 2, 4, 6, 8, 10, 12, 14 };

                y = arr[3] / size(arr) ;

                swapplus1(x, y);      print(x, y);

                swapplus2(x, y);      print(x, y);

                swapplus3(x, y);      print(x, y);

                swapplus4(&x, &y); print(x, y);

                int *px = &x, *py = &y;

                (*px)--;

                (*py) -= -7;

                swapplus5(px, py); print(x, y);

                return 0;

}

This program outputs 5 lines. What are they?

1.

2.

3.

4.

5.

Answer 1

A6)

line 1)x: 1 | y: 9
line 2)x: 0x408030 | y: 10
line 3)x: 3 | y: 4
line 4)x: 5 | y: 6
line 5)x: 4 | y: 2

A7) assuming size(arr) return sizeof arr (or is typo for sizeof(arr)) and the function is already declared

output:   x: 0 |y: 0
x: -1 |y: 1
x: -1 |y: 0
x: 1 |y: 0
x: 0 |y: 7

if size(arr) return no of elements in arr:

output:    x: 1 |y: 1
x: 0 |y: 2
x: 0 |y: 0
x: 2 |y: 1
x: 1 |y: 8

if size() function is not declared then an error will be given