Question

Given the following function in C++:

int main(void) {

int a = 2;

int b = myFunction(a);

a = b + 1;

b = myFunction(a);

cout << ”b = ” << b << endl;

return 0;

}

int z = myFunction(int x) {

static int n = 0;

n = n + 1;

int z = x + n;

return z;

}

What is printed by the cout on the screen?

Answer 1

Case:1

This program is getting Some syntax Errors

main.cpp: In function ‘int main()’: main.cpp:4:21: error: ‘myFunction’ was not declared in this scope int b = myFunction(a); ^ main.cpp:7:1: error: ‘cout’ was not declared in this scope cout << "b = " << b << endl; ^~~~ main.cpp:7:24: error: ‘endl’ was not declared in this scope cout << "b = " << b << endl; ^~~~ main.cpp: At global scope: main.cpp:10:20: error: expected primary-expression before ‘int’ int z = myFunction(int x) { ^~~ main.cpp:10:25: error: ‘myFunction’ was not declared in this scope int z = myFunction(int x) {

Case:2

If we ignore that