A bullet of mass 0.035 kg is fired horizontally with a speed of 71.7 m/s from a tall bridge. The bullet is in the air for 2.05 s. How far from the base of the bridge does it land?
Given that the bullet is fired horizontally with a speed of 71.7 m/s from the bridge.
So initial horizontal velocity,
Time of flight,
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Consider the horizontal motion of the bullet
There is no acceleration in horizontal direction, so horizontal velocity remains constant.
Horizontal velocity = Horizontal distance/time of flight
ANSWER:
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