Question

A vertical summit parabolic curve has vertical offset of 0.375 m. from the curve to the...

A vertical summit parabolic curve has vertical offset of 0.375 m. from the curve to the grade tangent at Station 10 + 050. The curve has a slope of +4% and -2% grades intersecting at the P.I. The offset distance of the curve at P.I. is equal to 1.5m. If the stationing of the P.C. is at 10 + 000.

Compute the

(a) required length of curve (b) horizontal distance of the vertical curve turning point from the point of intersection of the grades. (c) elevation of the vertical curve turning point if the elevation of P.T. is 86.42 m

Homework Answers

Answer #1

Please give rating if you like my work.

Thank you so much in advance!!

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A vertical parabolic curve is to connect a back tangent of -3% and a forward tangent...
A vertical parabolic curve is to connect a back tangent of -3% and a forward tangent of +4%. The change of grade is 0.60% per 20 m station. The stationing of PC is 17+428 with an elevation of 200 m. Compute the: a) length of the parabolic curve; b) stationing of PT (format: 00+000.00); c) elevation of PT; d) elevation of the lowest point of the curve; e) elevation at Station 17+544.67.
A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.6%...
A parabolic curve has a descending grade of -0.8% which meets an ascending grade of 0.6% at station 10+020. The maximum allowable change of grade per 20 m station is 0.20%. Elevation at station 10+020 is 240.60 m. a) Compute the length of the curve; b) Compute the horizontal distance of the lowest point from station 10+020; c) Compute for the vertical distance from PI to the curve; d) Compute the elevation of the lowest point of the curve; e)...
A vertical parabolic sag curve of Lapulapu underpass has grade of -4% followed by a grade...
A vertical parabolic sag curve of Lapulapu underpass has grade of -4% followed by a grade of +2% intersecting at station 12+150.80 at elevation 124.80 m. above sea level. The change of grade of the sag curve is restricted to 6%. Compute the length of curve. Compute the elevation of the lowest point of the curve. Compute the elevation at station 12+125.60
the rate of change of the grade of a parabolic summit curve is 0.5%. the grade...
the rate of change of the grade of a parabolic summit curve is 0.5%. the grade of ascending and descending tangents are 6% and -2.0% respectively. the elecation of VPT is 200 ft at Sta 15+80. determine the: a.) length of curve b.) elecation of the summit c.)location of the summit d.)the vertical distance from VPI to the curve e.)elevation at Sta 06+80
A 1,800 ft. long sag vertical curve (equal tangent) has PVC at Station 145+10 and elevation...
A 1,800 ft. long sag vertical curve (equal tangent) has PVC at Station 145+10 and elevation 1,280 ft. The initial grade is -2.5% and final grade is +4.8%. Determine the elevation and stationing of PVI and PVT.
A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The...
A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The length of the curve is 450.00 ft. The intersection of the grades is at 10+00 and the elevation at that point is 440.00. Compute the elevation of the +00 points on the curve. Then determine the location and elevation of the highest point on the curve. If there is an existing bridge at this location over the proposed road, and the elevation of its...
An equal-tangent crest vertical curve is being designed for a speed of 55 mph. The curve...
An equal-tangent crest vertical curve is being designed for a speed of 55 mph. The curve connects grades of 2% and -3.5% in the direction of interest. The curve high point is at station 110+00 and has an elevation of 500 ft. What is the station and elevation of the PVC and the PVI?
A 3.0% grade passing at station 20+00.00 at an elevation of 99.10 m meets a -2.0%...
A 3.0% grade passing at station 20+00.00 at an elevation of 99.10 m meets a -2.0% grade passing at station 20+50.00 at an elevation of 99.60 m. Please note that these two elevations and stations DO NOT correspond to BVC and EVC. a) Determine the station and elevation of the point of intersection of the two grades. b) If the highest point on the curve must lie at station 20+55.00, find the elevation of this point and the length of...
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade...
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade of +1.5%. The PVI of the two grades is at station 33 + 75 and elevation of 540 m above the datum level. The elevation at station 34 + 40 must be 541 m above the datum level in order to Accommodate a street, which crosses the road. Determine; ( According to TRH17) i. The length of the curve. ii. The elevation and station...
3.9) Two level sections of an east-west highway (G=0) are to be connected. Currently, the two...
3.9) Two level sections of an east-west highway (G=0) are to be connected. Currently, the two sections of highway are separated by a 1200m (horizontal distance) ,2% grade.the westernmost section of highway is the higher of the two and is at elevation 30m. If the highway has a 100km/h design speed, determine, for the crest and sag vertical curves required, the stationing and elevation of the PVCs and PVTs given that the PVC of the crest curve (on the westernmost...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT