Question

A crest vertical curve joining a +3 percent and a -4 percent grade is to be...

A crest vertical curve joining a +3 percent and a -4 percent grade is to be designed with a length of 2184 ft and the Station of BVC is ( 334 + 68) at an elevation of 217.24 ft. The distance from BVC at station (339 + :00) is

Engineering   Civil-Engineering   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

I am attaching the answer below in JPG file,if you completely understand the answer and if my answer is correct then please like my answer and if you have any doubt then comment below i will try my best to answer your queries.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
.A crest vertical curve joining a +3 percent and a-4 percent grade is to be designed...
.A crest vertical curve joining a +3 percent and a-4 percent grade is to be designed for 40 Km/h. If the tangents intersect at station (K20+ 60.00) at an elevation of 200 m, determine the stations and elevations of the BVC and EVC. Also, calculate the elevations of intermediate points on the curve at the whole stations.
An equal-tangent crest vertical curve is being designed for a speed of 55 mph. The curve...
An equal-tangent crest vertical curve is being designed for a speed of 55 mph. The curve connects grades of 2% and -3.5% in the direction of interest. The curve high point is at station 110+00 and has an elevation of 500 ft. What is the station and elevation of the PVC and the PVI?
Problem #4: Vertical curve A vertical curve is define by gradient lines. The gradient of the...
Problem #4: Vertical curve A vertical curve is define by gradient lines. The gradient of the back tangent is +4.2% and the gradient of the forward tangent is -3.75%. The BVC station is at 45+00 and has an elevation of 215.00 feet. For a vertical curve with a length of 12 stations, determine the following: a. The station and elevation of the PVI. b. The station and elevation of the EVC. c. The elevation of the vertical curve at station...
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to...
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to be connected by a vertical curve 400 ft long. The elevation of the BVC is 348.52. What is the... a. Elevation on the curve of the low/high point? b. Elevation of the curve at station 19+00 c. Elevation of the tangent at station 21+00 d. Elevation of the curve at station 21+50 e. Elevation of the curve at station 18+50
A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The...
A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The length of the curve is 450.00 ft. The intersection of the grades is at 10+00 and the elevation at that point is 440.00. Compute the elevation of the +00 points on the curve. Then determine the location and elevation of the highest point on the curve. If there is an existing bridge at this location over the proposed road, and the elevation of its...
a sag vertical curve joining -3.5%and a 1.5% grades the point of curve PC station is...
a sag vertical curve joining -3.5%and a 1.5% grades the point of curve PC station is 188 ft with an elevation of 175 ft assume K value for this highway is 180 determine the minimum length of the curve L determine the station of the endpoint of the curve PT determine the elevation of the point of intersection PL
a vertical curve joining 2.5% and a -3.5% grades.the point of curve (pc) station is (235.2)ft...
a vertical curve joining 2.5% and a -3.5% grades.the point of curve (pc) station is (235.2)ft with an elevation of 170 ft assume k value for this highway is 280 determine the minimum length of the curve (L) determine the elevation of the point of intersection (pi) determine the station of the point of intersection (pi)
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade...
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade of +1.5%. The PVI of the two grades is at station 33 + 75 and elevation of 540 m above the datum level. The elevation at station 34 + 40 must be 541 m above the datum level in order to Accommodate a street, which crosses the road. Determine; ( According to TRH17) i. The length of the curve. ii. The elevation and station...
) An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4%...
) An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4% and the final grade is negative. Draw the curve. What is the elevation difference between the PVC and the high point of the curve?
A vertical parabolic sag curve of Lapulapu underpass has grade of -4% followed by a grade...
A vertical parabolic sag curve of Lapulapu underpass has grade of -4% followed by a grade of +2% intersecting at station 12+150.80 at elevation 124.80 m. above sea level. The change of grade of the sag curve is restricted to 6%. Compute the length of curve. Compute the elevation of the lowest point of the curve. Compute the elevation at station 12+125.60
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT