Question

) An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4% and the final grade is negative. Draw the curve. What is the elevation difference between the PVC and the high point of the curve?

Answer #1

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An equal-tangent crest vertical curve is designed for 100 km/h.
The initial grade is +3.4% and the final grade is negative. Draw
the curve. What is the elevation difference between the PVC and the
high point of the curve?

An equal-tangent crest vertical curve is being designed for a
speed of 55 mph. The curve connects grades of 2% and -3.5% in the
direction of interest. The curve high point is at station 110+00
and has an elevation of 500 ft. What is the station and elevation
of the PVC and the PVI?

An
existing equal-tangent sag vertical curve is designed for 60 mi/h.
The initial grade is -3% and the elevation of the PVT is 754 ft.
The PVC of the curve is at station 134 + 16 and the PVI is at 137 +
32. An overpass is being constructed directly above the PVI. The
highway is for cars only (AASHTO minimum and recommended structure
clearances do not apply) and the overpass design assumes the
driver's eye height is set conservatively...

An existing equal-tangent sag vertical curve is designed for 60
mi/h. The initial grade is -3% and the elevation of the PVT is 754
ft. The PVC of the curve is at station 134 + 16 and the PVI is at
137 + 32. An overpass is being constructed directly above the PVI.
The highway is for cars only (AASHTO minimum and recommended
structure clearances do not apply) and the overpass design assumes
the driver's eye height is set conservatively...

.A crest vertical curve joining a +3 percent and a-4 percent
grade is to be designed for 40 Km/h. If the tangents intersect at
station (K20+ 60.00) at an elevation of 200 m, determine the
stations and elevations of the BVC and EVC. Also, calculate the
elevations of intermediate points on the curve at the whole
stations.

An equal tangent sag vertical curve is 600 ft long (i.e. 6
stations). The elevation of PVC is 1000 ft. The initial grade is
-0.035 ft/ft (-3.5%) and the final grade is +0.005 ft/ft (+0.5%).
What is the elevation of a point that is 350 ft (3.5 stations) from
PVC?
A) 1005.42 ft
B)991.83 ft
C) 991.01 ft
D) 996.83 ft

A 1,800 ft. long sag vertical curve (equal tangent) has PVC at
Station 145+10 and elevation 1,280 ft. The initial grade is -2.5%
and final grade is +4.8%. Determine the elevation and stationing of
PVI and PVT.

An equal-tangent crest vertical curve is 1919.200m long and
connects a +2.5%and –1.5%grade. If the design speed of the roadway
is 88.5 kph, does this curve have adequate passing-sight
distance?

A 182.880m equal tangent sag curve has the PVC at station
5+181.600 and elevation 304.800m. The initial grade is -3.5% and
the final grade is 0.5%. Determine the stationing and elevation of
the PVT, PVI and the lowest point on the curve.

A crest vertical curve joining a +3 percent and a -4 percent
grade is to be designed with a length of 2184 ft and the Station of
BVC is ( 334 + 68) at an elevation of 217.24 ft. The distance from
BVC at station (339 + :00) is

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