Question

If the reference electrode consists of a Cu/Cu2+ half-cell, what ion are you likely trying to...

If the reference electrode consists of a Cu/Cu2+ half-cell, what ion are you likely trying to measure?

Homework Answers

Answer #1

With out two electrodes we arew unable to measure electrode potential. Combining with SHE we can calculate potential of another electrode. Copper electrode and hydrogen electrode joined through voltmeter.

The electrons are flow2s from hydrogen to copper electrode.

The hydrogen electrode act as anode and copper act as cathode.

Reduction takes place at cathode.

At cathode : Cu+2 +2e- --------------> Cu

Here we get standard reduction potention of Cu.

Once we want to oxidation potential of Cu then we can reverse the sign of reduction potential.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C. The...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are 5.30×10−2 M and 1.50 M , respectively. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.350 V ?
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 C. The...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 C. The initial concentrations of Pb2+ and Cu2+ are 5.10x10^-2 M and 1.70 M respectively. What is the initial cell potential? What is the cell potential when the concentration not Cu2+ has fallen to 0.200M? What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.35V?
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C ....
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C . The initial concentrations of Pb2+ and Cu2+ are 5.30×10−2 M and 1.50 M , respectively. a) What is the initial cell potential? b) What is the cell potential when the concentration of Cu2+ has fallen to 0.200 M ? c) What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.370 V ?
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C. The...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are 5.10×10−2 M and 1.60 M , respectively. The initial potential is 0.51 V and the cell potential is 0.45 V when the concentration of Cu2+ has fallen to 0.230 M. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.350 V ?
Enter electrons as e-. A voltaic cell is constructed in which the anode is a Cu|Cu2+...
Enter electrons as e-. A voltaic cell is constructed in which the anode is a Cu|Cu2+ half cell and the cathode is a F-|F2 half cell. The half-cell compartments are connected by a salt bridge. (Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed, leave it blank.) The anode reaction is: + + The cathode reaction is: + + The net cell reaction is: + +...
A standard galvanic cell is constructed in which a Cu2+ | Cu+ half cell acts as...
A standard galvanic cell is constructed in which a Cu2+ | Cu+ half cell acts as the cathode. Which of the following statements are correct? Hint: Refer to a table of standard reduction potentials. (Choose all that apply.) As the cell runs, anions will migrate from the Cu2+|Cu+ compartment to the other compartment. Cu+ is oxidized at the cathode. The anode compartment could be Ag+|Ag. The anode reaction could be Fe -> Fe2+ + 2e-. In the external circuit, electrons...
One half of an electrochemical cell consists of a pure nickle electrode in a 0.001 molal...
One half of an electrochemical cell consists of a pure nickle electrode in a 0.001 molal solution, and the other half is a cadmium electrode immersed in a 0.5 molal solution. The electrode potential is given by , where is the standard electrode potential and c is the molal concentration of the ions in the solution. The cell potential is most likely? a) -0.65 V b) -0.15 V c) -0.073 V d) +0.75 V
A concentration cell based on the following half reaction at 280 K Cu2+ +2e Cu has...
A concentration cell based on the following half reaction at 280 K Cu2+ +2e Cu has initial concentrations of 1.37 Cu 2+, 0.215 Cu2+, and a potential of 0.02314 V at these conditions. After 9.1 hours, the new potential of the cell is found to be 0.009826 V. What is the concentration of Cu2+ at the cathode at this new potential? a. 0.697 b. 0.871 c. 1.09 d. 1.36 e. 1.70
For the following two problems use the given half reactions to "construct" a galvanic cell. Cu2+...
For the following two problems use the given half reactions to "construct" a galvanic cell. Cu2+ + 2 e- → Cu      Eocell=0.34 V Ca2+ + 2 e- → Ca      Eocell=-2.76 V Which of the following statements about this galvanic cell is FALSE? 1) The mass of the Ca electrode will increase during the course of the reaction 2) Negatively charged ions will flow from the salt bridge toward the anode 3) The potential of this cell (at standard conditions) will...
The Ksp of copper(II) ferrocyanide(Cu2[Fe(CN)6]) is 1.3×10−16 at 25°C. Determine the potential of a concentration cell...
The Ksp of copper(II) ferrocyanide(Cu2[Fe(CN)6]) is 1.3×10−16 at 25°C. Determine the potential of a concentration cell in which one half-cell consists of a copper electrode in 1.00 M copper(II) nitrate, and the other consists of a copper electrode in a saturated solution of Cu2[Fe(CN)6]. Ferrocyanide, ([Fe(CN)6]4−), is a complex ion.