Question

Suppose that diastolic blood pressures of adult women in the United States are approximately normally distributed with mean 80.5 and standard deviation 9.9. What proportion of women have blood pressure greater than 67.6 ? Write only a number as your answer. Round to 4 decimal places (for example 0.0048). Do not write as a percentage.

Answer 1

Let , X be the diastolic blood pressures of adult women in the United States

X follows normal distribution with mean = = 80.5 and standard deviation = = 9.9

We have to find P( x > 67.6 ).

P( x > 67.6 ) = 1 - P( x <= 67.6 )

Using Excel function , =NORMDIST( x , , , 1 )

P( x <= 67.6 ) = NORMDIST( 67.6 , 80.5 , 9.9 , 1 ) = 0.096282

So, P( x > 67.6 ) = 1 - 0.096282 = 0.9037

Answer - Probability that women have blood pressure greater than 67.6 is 0.9037