Question

One half of an electrochemical cell consists of a pure nickle electrode in a 0.001 molal...

One half of an electrochemical cell consists of a pure nickle electrode in a 0.001 molal solution,

and the other half is a cadmium electrode immersed in a 0.5 molal solution. The electrode

potential is given by , where is the standard electrode potential and c is the molal concentration

of the ions in the solution. The cell potential is most likely?

a) -0.65 V

b) -0.15 V

c) -0.073 V

d) +0.75 V

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Homework Answers

Answer #1

Standard electrode potential for Cd and Ni are

E0Cd2+/Cd = -0.403 V and E0Ni2+/Ni = -0.250 V

Hence Cd2+/Cd will be the anode and Ni2+/Ni will be the cathode

Using Nernst equations

E = E0 + (0.059/2) * log (Cion)

ECd2+/Cd = E0Cd2+/Cd + (0.059/2)log(0.5) =-0.403 + (0.059/2)log(0.5) = -0.4118 V

Similarly,

ENi2+/Ni = E0Ni2+/Ni + (0.059/2)log(0.5) =-0.250 + (0.059/2)log(0.001) = -0.3385 V

Cell potential will be

E = ENi2+/Ni - ECd2+/Cd = -0.3385 – (-0.4118) = + 0.0733 V

note: may be the option " c) -0.073" be replaced by the option " c) +0.073"

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