(1) f = Σ m(2, 4, 6, 7)
(2) f = Π Μ(2, 4, 5, 6, 7)
(3) f = Σ m(0, 2, 3, 5, 6, 7,8,10,13,15)
(4) f = Π M(0, 2, 5,7,13,14,15) + D(3, 4, 6, 8,10, 11)
(5) f = Σ m(0, 1, 4, 5, 6, 8, 10, 11, 12, 13, 14, 15, 16, 17,
18, 19, 20, 21, 24, 26, 27, 28, 30, 31)
(Hint: Draw Karnaugh maps for both SOP and POS forms and then
obtain the simplified expression by covering 1s (for SOP form) or
covering 0s (for POS form). Then design circuits and compare the
cost. Circle your lowest cost solution. You should consider two
equivalent circuits to compare cost, which means you need to
minimize K map for f = SOP (0, 1, 6, 7) - covering 1s, and f = POS
(2, 3, 4, 5) - covering 0s)