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Balance the following redox equation in acid MnO4-+SCN---> SO4^-2+CN-+Mn2+

Balance the following redox equation in acid MnO4-+SCN---> SO4^-2+CN-+Mn2+

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Answer #1

MnO4-+SCN---> SO4^-2+CN-+Mn2+

first half reaction

MnO4^-   ...............> Mn^+2

add 4H2O molecules on the left side

MnO4^-   ...............> Mn^+2 + 4H2O

MnO4^- + 8H+ + 5e- ...............> Mn^+2 + 4H2O .....................1

second half reaction

SCN^- .............> SO4^-2 + CN-

add 4H2O molecules on the left side

SCN^- + 4H2O.............> SO4^-2 + CN-

add 8H+ ions on the left side

SCN^- + 4H2O .............> SO4^-2 + CN- + 8H+ + 6e- .................................2

eq.1*6 + eq.2*5

5SCN^- + 6MnO4^- + 8H+ .............> 5SO4^-2 +5 CN- + 4H2O + 6Mn^+2

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