Complete the following
Mn2+(aq) + F2(g) --> F-(aq) + MnO4-(aq)
a. Balance the redox equation above in acidic solution. Show work for full credit.
b. Circle the reducing agent in this redox reaction.
c. Calculate Eo for this reaction
a) balanced reaction :
2 Mn+2 + 5 F2 + 8H2O ------------------> 2 MnO4- + 10 Br- + 16 H+
oxidation half reaction:
Mn+2 -----------------> MnO4-
full balnaced in acidic medium :
Mn+2 + 4H2O -----------------> MnO4-
electron balced :
Mn+2 + 4H2O -----------------> MnO4- + 5e- (1)
reduction half reaction:
F2 + 2e- --------------------> 2 F- (2)
multiply 1 with 2 and 2 with 5 we get full equation.
b) reducing agent : Mn+2
oxidising agent F2
c)
Eocell = 2.87 -1.507
Eocell = 1.363 V
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