Question

Balance out these equations: FeSO4 + K4Fe(CN)6 = Fe4[Fe(CN)6]3 + ?? FeSO4 + K3Fe(CN)6 = ??...

Balance out these equations:

FeSO4 + K4Fe(CN)6 = Fe4[Fe(CN)6]3 + ??

FeSO4 + K3Fe(CN)6 = ??

FeCl3 + K4Fe(CN)6 = ??

FeCl3 + K3Fe(CN)6 = ??

In some of these, I should also get K2Fe2(CN)6, but I do not know in which one.

In acid: Fe2O3 + CO => Fe + CO2

In acid: HCOOH + MnO4 - => CO2 + Mn2+

In acid: P + Cu2+ => Cu + H2PO4 -

In base: CO + I2O5 => CO2 + I2

In base: Cr(OH)3 + Br2 => CrO4 2- + Br-

Homework Answers

Answer #1

1).

3 K4(Fe(CN)6) + 6 FeSO4 = Fe4[Fe(CN)6]3 + 6 K2SO4 + Fe2

Fe4[Fe(CN)6]3 is the Prussian blue or Berlin blue.

2).

4K3[Fe(CN)6] + 3FeSO4 → Fe4[Fe(CN)6]3 + 3K2SO4 + 6KCN

Potassium hexacyanoferrate(III) react with iron(II) sulfate to produce iron(III) hexacyanoferrate(II), potassium sulfate and potassium cyanide.

3).

FeCl3 + K4[Fe(CN)6] ==> KFe[Fe(CN)6] + 3 KCl

Iron(III) chloride react with potassium hexacyanoferrate(II) to produce potassium diiron(III) hexacyanoferrate and potassium chloride.

4).

K3[Fe(CN)6] + FeCl3 → Fe[Fe(CN)6] + 3KCl

Potassium hexacyanoferrate(III) react with iron(III) chloride to produce iron(III) hexacyanoferrate(III) and potassium chloride.

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