Balance the Redox Equation using the 1/2 rxn method:
1.) S2O32-(aq) + I2(aq)
---> S4O62- (aq) +
I-(aq)
Balance the Redox Equation using the 1/2 rxn method
(acidic):
1.) HSO3-(aq) +
MnO4-(aq) ---> Mn2+ (aq) +
SO42- (aq)
2.) H2O2(aq) ---> O2(g)
Balance the Redox Equation using the 1/2 rxn method
(basic):
1.) HSO3-(aq) +
MnO4-(aq) --->
MnO42-(aq) +
SO42-(aq)
2.) MnO42-(aq) ---> MnO2
(aq)
Ans 1 :
Start balancing the reaction by writing the two half reaction oxidation and reduction seperately.
Then balance all the other atoms , except hydrogen and oxygen.
Balance oxygen and hydrogen atoms by adding water molecules and protons respectively.
Now add electrons to balance the charges , and then make electron gain = electron lost.
Then add the two half reactions together and simplify,to get the balanced reaction as :
2S2O32-(aq) + I2(aq) ---> S4O62- (aq) + 2I-(aq)
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