Question

Please simplify as much as possible. Something isnt clicking for me.

1.How many moles of ammonia (NH3) are in 68.5 g of the compound?

2.How many grams of Br are in 155 g of CaBr2?

Answer 1

1.How many moles of ammonia (NH3) are in 68.5 g of the compound?

moles = W/Mw= 68.5/17 = 4.029mole

2.How many grams of Br are in 155 g of CaBr2?

CaBr2 wight = 199.88gm

CaBr2 moles = 155/ 199.88= 0.775moles

Ca moles = 0.775 ,   Br moles = 2 x 0.775= 1.55

bromine wt = moles x molar mass

                   = 1.55 x(159/2)

                  Br weight = 123.2g