Question

1) How many grams of NH3 can be produced from 4.48 mol of N2 and excess H2.

Express your answer numerically in grams.

2) How many grams of H2 are needed to produce 11.93 g of NH3?

Express your answer numerically in grams.

3)How many molecules (not moles) of NH3 are produced from 4.38×10⁻⁴ g of H2?

Express your answer numerically as the number of molecules.

Answer 1

Answer 3 (continued)

17 g of NH₃ = 6.022 x 10²³ molecules

2.48 x 10^-3 g of NH₃

= [(6.022 x 10²³ molecules)/17 g]*2.48 x 10^-3 g

= 8.79 x 10¹⁹ molecules of NH₃.