Question

Suppose that, at equilibrium, all of the CO2 is removed using CaO. How will concentrations of the remaining gases response? Reaction: CO + H2O -> CO2 + H2,

4.00atm = CO,

4.00atm = H2O,

Kp = 10

Answer 1

               CO + H2O ------> CO2 + H2

initially    4         4                  0         0

at equi   (4-x)   (4-x)             x          x

Kp = P CO2 . PH2 / PCO . PH2O

10 = x^2 / (4-x)^2

x = 3.03898 atm

at equilibrium P CO = 4 - 3.039 = 0.961 atm = P H2O

if we remove all the CO2 then there will be more pressure of CO and H2O so they react together and produces CO2 and H2.

hence all reactancts are reacted to give final products if we remove the CO2 from the reaction.