Question

What standard conditions do we assume when calculating the standard free energy of formation?

What standard conditions do we assume when calculating the standard free energy of formation?

Homework Answers

Answer #1

The standard Gibbs free energy of formation of a compound is the change of Gibbs free energy that accompanies the formation of 1 mole of that substance from its component elements, at 25 degrees Celsius and 101.3 kilopascals (or 1 atm).

The standard conditions other than 25 degree celsius are

  1. For a gas: the standard state is a pressure of exactly 1 atm
  2. For a solute present in an ideal solution: a concentration of exactly one mole/liter (M) at a pressure of 1 atm
  3. For an element: the form in which the element is most stable under 1 atm of pressure.
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Under standard conditions, the free energy of formation (ΔGof) of CO2 ­(g) is -394 kJ/mol. C...
Under standard conditions, the free energy of formation (ΔGof) of CO2 ­(g) is -394 kJ/mol. C (s) + O2 (g) → CO2 (g) Assuming the temperature remains 25 oC and the partial pressure of O2 (g) remains 1 atm, what would be the value of ΔG for this reaction when the partial pressure of CO2 ­(g) is 7.88 x 10-3 atm?
The standard free energy of formation of KBr(s) is –380.4 kJ/mol.  What is delta G° for the...
The standard free energy of formation of KBr(s) is –380.4 kJ/mol.  What is delta G° for the reaction 2KBr(s) --> 2K(s) + Br2(l) ?
The standard Gibbs free energy of formation of ________ is zero. (a) Ba(s) (b) N2(g) (c)...
The standard Gibbs free energy of formation of ________ is zero. (a) Ba(s) (b) N2(g) (c) Cs(s) The standard Gibbs free energy of formation of ________ is zero. (a) (b) (c) (a) only (b) only (c) only (b) and (c) (a), (b), and (c)
What are we calculating when we calculate expected frequencies? What is the reason for calculating expected...
What are we calculating when we calculate expected frequencies? What is the reason for calculating expected frequencies the way we do? In laymen’s term, what do expected frequencies tell us? the previous answer to the same question really did not answer all the questions. like the laymen’s term for expected frequency. and the reason for calculating it.
For the hydrolysis of ATP to ADP + ℗i, the free-energy change is -7.3 kcal/mol under...
For the hydrolysis of ATP to ADP + ℗i, the free-energy change is -7.3 kcal/mol under standard conditions (1 M concentration of both reactants and products). In the cellular environment, however, the free-energy change is about -13 kcal/mol. What can we conclude about the free-energy change for the formation of ATP from ADP and ℗i under cellular conditions?
24) a) Why don’t we consider the phonon energy when calculating the energy of emitted photons...
24) a) Why don’t we consider the phonon energy when calculating the energy of emitted photons in an indirect gap materials? b) Why is the phonon energy important for an electron changing its energy in the conduction band or a hole changing its energy in the valence band?
Identify the compound with the standard free energy of formation equal to zero. A) NaCl(s) B)...
Identify the compound with the standard free energy of formation equal to zero. A) NaCl(s) B) N2(g) C) NO(g) D) O3(g) E) It is hard to determine. I know the answer is B,but don't understand why. Please explain!
Under standard conditions, NADH reoxidation by the electron-transport chain has a free-energy change equal to –220...
Under standard conditions, NADH reoxidation by the electron-transport chain has a free-energy change equal to –220 kJ/mol. With 100% efficiency, how many ATP could be synthesized under standard conditions? What is the “actual” efficiency given these numbers?
Which system (open, closed, or isolated) do we infer when describing Gibbs free energy calculation AND...
Which system (open, closed, or isolated) do we infer when describing Gibbs free energy calculation AND WHY? I think the system is Isolated, but I don't know why...
Assume we know the Gibbs free energy of reaction for a chemical reaction taking place at...
Assume we know the Gibbs free energy of reaction for a chemical reaction taking place at 298 K. What additional thermodynamic information do we need to know to compute the equilibrium constant of the reaction (a) at 298 K and (b) at 350 K? (You may assume that no phase transitions take place in this temperature range.)