Question

true or false??? if methane decomposition occurs at 1000K and 10 atm, the equilibrium mole fraction of H2 does not exceed 60%

Answer 1

The answer is False.

When one mole of methane decomposes thermally it produces one mole of carbon and 2 moles of hydrogen gas, the equation is written as follows.

CH4 -----------------> C + 2H₂

Here the total number of moles of Hydrogen at equilibrium could be only C and 2H2 gas because all of the methane is converted to Carbon and hydrogen gas. So now it is only the mole fraction of C and H2 in such case H2 has two moles and Carbon has one mole. So the mole fraction of Hydrogen is 2/3*100%= 66.6% which is greater than 60%