hat concentration of Br– results when 883 mL of 0.707 M KBr is mixed with 945 mL of 0.629 M FeBr2?
concentration of Br- = moles in KBr + moles in FeBr2 / total volume
= 883 x 0.707 + 2 x 945 x 0.629 / (945 + 833)
= 0.992 M
concentration of Br- = 0.992 M
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