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hat concentration of Br– results when 883 mL of 0.707 M KBr is mixed with 945...

hat concentration of Br– results when 883 mL of 0.707 M KBr is mixed with 945 mL of 0.629 M FeBr2?

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Answer #1

concentration of Br- = moles in KBr + moles in FeBr2 / total volume

                               = 883 x 0.707 + 2 x 945 x 0.629 / (945 + 833)

                               = 0.992 M

concentration of Br-   = 0.992 M

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