Question

What NaCl concentration results when 224 mL of a 0.690 M NaCl solution is mixed with 522 mL of a 0.490 M NaCl solution?

Answer 1

Concentration of mixture = (C1*V1+ C2*V2) / (V1+V2)

where C1 --> Concentration of 1 component

V1-->volume of 1 component

C2 --> Concentration of other component

V2-->volume of other component

Here

C1 = 0.69 M

C2 = 0.49 M

V1 = 224.0 mL

V2 = 522.0 mL

we have below equation to be used:

C = (C1*V1+ C2*V2) / (V1+V2)

C = (0.69*224+0.49*522)/(224+522)

C = 0.550 M

Answer: 0.550 M