Question

Calculate the concentration of OH^- when 2.00 ml of 0.05M NaOH are mixed with 5.00 ml of CV (Crystal Violet) solution.

Answer 1

CV + NaOH ----> CVOH

1mole CV = 1mole NaOH

When 2.00mL of 0.05M NaOH reacts with 5.00 mL of CV can be calculated as follows

M1V1 = M2V2

M1= 0.05M, V1 = 2.00mL, M2=?, V2=5.00mL

Molarity of CV, M2 = M1V1/V2 = 0.05*2/5 = 0.02 M

The concentration of CV is = 0.02M

Therefore volume of NaOH required to completely react with 0.02M of 5.00mL CV = V1= M2V2/M1

V1 = 0.02*5/0.05 = 2mL

Amount of NaOH required to neutralize 0.02M of 5.00mL of CV is = 2ml

The concentartion of NaOH remians= 0 M