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What concentration of NO3– results when 925 mL of 0.729 M NaNO3 is mixed with 799...

What concentration of NO3– results when 925 mL of 0.729 M NaNO3 is mixed with 799 mL of 0.565 M Ca(NO3)2? (show work)

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Answer #1

in mixed solution :

concentration of NO3- = mmoles of NO3- in NaNO3 + mmoles of NO3- in Ca(NO3)2 / total volume

concentation of NO3 - = 925 x 0.729 + 2 x (799 x 0.565) / (799 + 925)

                                                     = 0.915 M

concentation of NO3 -   = 0.915 M

                                                       

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